
n is an integer, so 2n+1 is also an integer. 8s+1 is equal to the square of 2n+1, so it's a square number.
2n+1 is an odd integer for any value of n. The square of an odd integer is always an odd integer. Therefore 8s+1=(2n+1)² is odd.
8s+1 is an odd square number.
Answer:
C) 
Step-by-step explanation:
0.51 repeating decimal
x= 0.51515151
multiply by 100 on both sides
100x = 51.515151.........
x= 0.515151...............
--------------------------------------------(subtract)
99x = 51
divide by 99 on both sides

divide both sides by 3

Answer:
250 minutes of calling will cost same using both plans.
$53
Step-by-step explanation:
Please consider the complete question.
A phone company offers two monthly plans. Plan A costs $23 plus an additional $0.12 for each minute of calls. Plan B costs $18 plus an additional $0.14 of each minute of calls. For what amount of calling do the two plans cost the same? What is the cost when the two plans cost the same?
Let x represent the number of call minutes.
The total cost of calling for x minutes using plan A would be cost of x minutes plus fixed charge that is
.
The total cost of calling for x minutes using plan B would be cost of x minutes plus fixed charge that is
.
To find the number of minutes for which both plans will have same cost, we will equate total cost of x minutes for both plans and solve for x.







Therefore, calling for 250 minutes will cost same using both plans.
Upon substituting
in expression
, we will get:

Therefore, the cost will be $53, when the two plans cost the same.
The time she will be done with her breakfast is by = 10:48 am
<h3>Conversation of time</h3>
The time Megan started her breakfast = 9:54 AM.
In terms of hours = 9
In terms of minutes = 54
If she takes the given number of minutes to eat which is = 54 mins .
Therefore, the time she will be done with her breakfast is = 9:54 + 54
= 10: 48 am
Learn more about time here:
brainly.com/question/10428039
Answer:
x = 2000 cameras
Step-by-step explanation:
C(x) Total cost in producing x units
C- = C(x) /x Average cost of producing x units x > 0
Cannon Precision Instrument
C (x) Total monthly cost for producing x units of M1 cameras
is C(x) = 0.0025x² + 80x + 10000
Then average cost of producing x cameras M1 is
C-(x) = ( 0.0025x² + 80x + 10000) /x
C-(x) = 0.0025x + 80 + 10000/x
Taking derivatives on both sides of the equation
C-´(x) = 0.0025 - 10000/x²
Then
C-´(x) = 0
( 0.0025x² - 10000 ) / x² = 0
0.0025x² - 10000 = 0
x² = 10000 /0.0025 x² = 4000000
x = 2000 cameras