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Evgen [1.6K]
3 years ago
13

Back at it again. At not getting math.

Mathematics
1 answer:
NARA [144]3 years ago
7 0

Answer:

168 {m}^{3}

Step-by-step explanation:

Volume of pyramid= \frac{1}{3}  \times base \: area \times height

Thus, volume of rectangular pyramid

=  \frac{1}{3} (9)(8)(7) \\  = 168m^{3}

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Which postulate can be used to prove the two triangles are congruent?
Scorpion4ik [409]

Answer:

None of them i think

Step-by-step explanation:

6 0
3 years ago
an anchor line for a tower needs to be replaced. the tower is 96ft tall. the anchor line is 105ft long. how far from the tower c
Fynjy0 [20]

Answer:

Let x be how far from the tower can it be placed

by Pythagorus theorem

x^2  + 96^2   = 105^2

x=√(105^2  -96^2 )=√1809 = 42.532340 = 42.5 ft


3 0
3 years ago
5. A sum of money is divided among Ethan, Jun Wei
anastassius [24]

Answer:

$450

Step-by-step explanation:

Let E be the amount of money Ethan starts with, J be the amount Jun Wei starts with, and R be the amount Raj starts with. Let M be the total amount of money to start with.

To start:

E:J:R = 5:6:9

This means Ethan has 5/20 of M, the money to start with. This reduces to 1/4 of M.

Afterwards:

(E-50):J:R = 3:4:6

This means Ethan has 3/13 of the remaining money (which is M-50!) after giving up 50. So

E = (M/4), or 4E = M

and

(E - 50) = 3/13 * (M - 50)

We know 4E = M, so we can substitute that in:

(E - 50) = 3/13 * (4E - 50)E - 50 = (12/13)E - 150/13E - 650/13 = (12/13)E - 150/13(1/13)E = 500/13E = 500

That's how much money Ethan had to start with. But we're asked how much he has AFTER giving $50 away, so that's $450.

3 0
3 years ago
In the triangle below what is the approximate value of x
sveta [45]
You can solve using the pythagorean theorem which is

a^2+b^2=c^2 where a and b are the legs and c is the hypotenuse in a right triangle.

12^2+x^2=24^2
144+x^2=576
x^2=432
x =20.78 (approximately)
4 0
3 years ago
Read 2 more answers
What is the recursive formula for this geometric sequence?–2, –16, –128, –1024, ...
Tatiana [17]

Answer:

b_n=-2\cdot 8^{n-1}

Step-by-step explanation:

Denote first four terms of the geometrc sequence as

b_1=-2,\\ \\b_2=-16,\\ \\b_3=-128,\\ \\b_4=-1024.

Note that

b_2=b_1\cdot q\Rightarrow -16=-2\cdot 8;\\ \\b_3=b_2\cdot q\Rightarrow -128=-16\cdot 8;\\ \\b_4=b_3\cdot q\Rightarrow -1024=-128\cdot 8.

Then the common ratio is

q=8.

Therefore, the recursive formula for the geometric sequence is

b_n=b_1\cdot q^{n-1}\Roghtarrow b_n=-2\cdot 8^{n-1}.


5 0
3 years ago
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