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Elena L [17]
3 years ago
10

Use the Quadratic Formula to find the exact solutions of x2 + 7x - 4 = 0.

Mathematics
1 answer:
sladkih [1.3K]3 years ago
3 0

Answer:

The solution of equation x^2+7x-4=0 is 0.53,-7.53.

Step-by-step explanation:

Given : Quadratic equation x^2+7x-4=0

To find : The solution of equation ?

Solution :

The solution of the quadratic equation ax^2+bx+c=0 is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Here, a=1, b=7 and c=-4.

Substitute the values,

x=\frac{-7\pm\sqrt{7^2-4(1)(-4)}}{2(1)}

x=\frac{-7\pm\sqrt{65}}{2}

x=\frac{-7+\sqrt{65}}{2},\frac{-7-\sqrt{65}}{2}

x=0.53,-7.53

Therefore, the solution of equation x^2+7x-4=0 is 0.53,-7.53.

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Y = 5x + 2
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Answer:

y = 5x + 2 . . . . . . . . . . (1)

3x = -y + 10 . . . . . . . . (2)

3x = -(5x + 2) + 10

3x = -5x - 2 + 10                                            

3x + 5x = -2 + 10

8x = 8

x = 1

y = 5(1) + 2 = 5 + 2 = 7

Solution is (1, 7)                                     The answer is (1,7)

Step-by-step explanation:

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2 years ago
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2 years ago
Convert 2 2/5 meter to cm
harina [27]
2.4 meters x 100 = 240cm
7 0
2 years ago
A conical cup is made from a circular piece of paper with radius 10 cm by cutting out a sector and joining the edges as shown be
SVEN [57.7K]
Part a:

The opening of the cup is the circular base of the cup which has a circumference equal to the length of the arc formed by angle <span>θ = 9π/5 on the circular piece of paper from which the cone was made.

Thus, the circumference of the circle = Length of the arc formed by angle </span>θ = 9π/5 at the center which is given by
C=r\theta \\  \\ =10\times \frac{9\pi}{5}  \\  \\ =18\pi\approx56.55\ cm


Part b:
The opening of the cup is the circular base of the cup which has a circumference equal to the length of the arc formed by angle <span>θ = 9π/5 on the circular piece of paper from which the cone was made.

</span>Recall that the circumference of a circle is given by C=2\pi r and having obtained from part a that the circumference of the circular opening is 18\pi cm.

Thus,
2\pi r=18\pi \\  \\ \Rightarrow r=9\ cm


Part c:
The height of the cup can be obtained by noticing that the radius, height and the slant height of the cup forms a right triangle with the height and the radius as the legs and the slant height as the hypothenus.

Using pythagoras theorem, the height of the cup is obtained as follows:
h^2+r^2=l^2
where: h is the height, r is the radius and l is the slant height.

h^2+9^2=10^2 \\  \\ \Rightarrow h^2=100-81=19 \\  \\ \Rightarrow h= \sqrt{19} \approx4.36\ cm


Part d
Recall that the volume of a cone is given by V= \frac{1}{3} \pi r^2h

Thus, the volume of the cup is given by
V= \frac{1}{3} \pi\times9^2\times \sqrt{19}  \\  \\ \approx369.7\ cm^3
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