<h3>The exact probability that the blue ball is drawn first and the red ball is drawn second is
</h3>
<em><u>Solution:</u></em>
<em><u>The probability of an event is given as:</u></em>
Given that,
There are 12 balls in a bag
One is blue and one is red
Favorable outcome = blue ball is drawn first
Favorable outcome = 1
Therefore,
Now, without replacement, red ball is drawn second
Therefore,
Total possible outcomes = 12 - 1 = 11
<em><u>What is the exact probability that the blue ball is drawn first and the red ball is drawn second?</u></em>
Thus the exact probability that the blue ball is drawn first and the red ball is drawn second is
Answer:
no thank you sorry 4h he'll be a great day of school and I have been a while ago but it's a good time 44
Here are the steps to the answer. Answer: y=x+2
Tahmid has 96 figures, Sandeep has 1/3 of it so
96(1/3) = 96/3 = 32
Sandeep has 32 figures
Tahmid 96 ; Sandeep 32
How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give.
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each.
