Remember these two combinations: logab=loga+logb, log(a/b)=loga-logb
3logx=logx^3
(1/2)log(x+2)=log(x+2)^(1/2)
2log(z-4)=log(z-4)^2
so the given expression can be combined into log{[(x^3)(z-4)^2]/(x+2)^(1/2)}
Answer:
The questions and problem can be chosen in 1260 ways.
Step-by-step explanation:
Given that, a physics exam consists of 6 open-ended problem and 9 multiple choice questions.
The order of choosing does not matter.
So,we use combination to find ways.
The ways to choose 6 multiple choice from 9 is= 

=84
The ways to 2 open-ended question from 6 is= 

=15
Since pick 6 multiple choice out of 9 and 2 open-ended question out of 6 both are independent we have multiply both to find required ways.
Total number of ways is =(84×15)
=1260.
Recognize that you must combine "like" terms. 5x^2y and x^2y are "like" terms.
Adding them together, you get 6x^2y.
Now add 2xy^2 to 6x^2y. These are NOT "like" terms, so you end up with
6x^2y+2xy^2 as your final answer. This answer is acceptable as is.
However, you could factor out the common factors: 2xy(3x+y).
You just have to multiply each number by 180 and that's how many you have of each color respectively
0.5u + 2v. This is because u can separate the logs to ln(sqrx) + ln(y^2) and use basic log principles to get 0.5lnx +2lny. Then u substitute