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Bogdan [553]
3 years ago
12

A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee

must answer 6 of the multiple-choice questions and 2 of the open-ended problems, in how many ways can the questions and problems be chosen?
Mathematics
1 answer:
Mariana [72]3 years ago
6 0

Answer:

The questions and problem can be chosen in 1260 ways.

Step-by-step explanation:

Given that, a physics exam consists of 6 open-ended problem and  9 multiple choice questions.

The order of choosing does not matter.

So,we use combination to find ways.

The ways to choose  6 multiple choice from 9 is= ^9C_6

                                                                              =\frac{9!}{6!(9-6)!}

                                                                              =84

The ways to 2 open-ended question from 6  is= ^6C_2

                                                                              =\frac{6!}{2!(6-2)!}

                                                                             =15

Since pick 6 multiple choice out of 9 and 2 open-ended question out of 6 both are independent we have multiply both to find required ways.

Total number of ways is =(84×15)

                                        =1260.

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A standard deck of cards contains 52 cards. The cards have 4 different suits: clubs, diamonds, hearts, and spades. For each suit
Taya2010 [7]

Answer:

a. 108336, b. 480200

Step-by-step explanation:

a. No. of ace cards = 4

No. of non ace cards= 48

We draw 5 cards

So,

No. of ways of 2 aces = C(4,2) C(48,3)

No. of ways of 3 aces = C(4,3) C(48,2)

No. of ways of 4 aces = C(4,4) C(48,1)

Hence

No. of ways of 2 or more aces

= C(4,2) + C(48,3) + C(48,3) + C(4,3)C(48,2) +C(4,4)C(48,1)

= 6(17296) + 4(1128) + (48)

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b. No of ways any 5 cards can be chosen = C(52,5)

No. of ways kings of diamonds or queen of hearts is chosen = C(50,5)

Hence

No. of ways of choosing king of diamonds, queen of hearts or both = C(52,5) – C(50,5)

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4 0
2 years ago
Can you give an example of equations when you are given the constant of proportionality?
aleksandr82 [10.1K]
Example:
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2 years ago
A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 410 gram setting. It is
frozen [14]

Answer:

The decision rule for rejecting the null hypothesis is t < -1.721

Step-by-step explanation:

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 410 gram setting. It is believed that the machine is underfilling the bags.

At the null hypothesis, we test if the mean weight of the bag is the desired value of 410, that is:

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At the alternate hypothesis, we test if the bag is underfilled, that is, the mean weight is below the desired value, so:

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Type of test:

As we test if the mean is less than a value, we have a left-tailed test.

We have the standard deviation for the sample, which means that the t-distribution is used.

We have 22 - 1 = 21 degrees of freedom, with a level of significance of 0.05.

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We reject the null hypothesis if the test statistic is less than the critical value, so the decision rule for rejecting the null hypothesis is t < -1.721

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 0
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Answer:

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Step-by-step explanation:

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