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serg [7]
3 years ago
13

Each leg of a 45 45 90 triangle has a length of 6 what is the length of its hypotenuse

Mathematics
1 answer:
Reika [66]3 years ago
7 0
Let x = the length of the triangle's hypotenuse
using proportions, this is what the equation looks like:

cross multiply to get:

divide both sides by 45 to get 
x=12
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Which is the longest 2 km 25m 2500 cm or 3000 mm
MAVERICK [17]
2km=2 kilometer
kilo=1000 so 2 km=2000m

25m

2500cm
cm=centimeter=1/100 of a meter
so
2500cm=25m


mm=milimeter=1/1000 meter
so
3000mm=3m

so the longets is obviously 2000m or 2km
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2 years ago
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I need 3 multiples of 10 that has 3 as one of the digits
d1i1m1o1n [39]
3 multiples of 10 that have 3 in them are 30, 300, and 3000
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How would I solve <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20x-%5Cfrac%7B5%7D%7B3%7D%20%3D-%5Cfrac%7B1%7D%7B2%7D%
sdas [7]
Multiply both sides of the equation by 12. Move the variables to the left-hand side and change its sign. Move the constant to the left-hand side and change its sign. Collect like terms. Add the numbers. Divide both sides of the equation by 12.

1/2 x - 5= - 1/2 x + 19/4
6x -20= - 6x + 57
6x + 6x= 57 + 20
12x= 57 + 20
12x= 77
ANSWER
x = 77/12
Alternative Form .
x = 6 5/12, x= 6.416
7 0
2 years ago
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Allan drew a polygon with 4 sides and 4 angles. All four sides are equal. None of the angles are right angles. What figure did A
Lady_Fox [76]

Answer: The figure drawn by Alan is a rhombus.


Step-by-step explanation:

Given: Allan drew a polygon with 4 sides and 4 angles with two properties:-

  • All four sides are equal.
  • None of the angles are right angles.

We know that only a rhombus is a flat shape with 4 equal straight sides and 4 angles .All sides have equal length. Its angles need not to be right angle.

Therefore, the figure drawn by Alan is a rhombus.


8 0
2 years ago
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A researcher believes that the mean weight of competitive runners is about 140 pounds. A sample of 24 elite distance runners has
ExtremeBDS [4]

Answer:

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

p_v =P(t_{(23)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=136 represent the sample mean

s=11 represent the sample standard deviation

n=24 sample size  

\mu_o =140 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 140, the system of hypothesis would be:  

Null hypothesis:\mu \geq 140  

Alternative hypothesis:\mu < 140  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=24-1=23  

Since is a one left tailed test the p value would be:  

p_v =P(t_{(23)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

4 0
2 years ago
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