The length of one side of a triangular lot is 6 m less than 3 times the length of the second side. The third side is 8 m longer
than the first side. The perimeter of the lot is 80 m. Find the length of all three sides.
1 answer:
second side = x
first side = 3x - 6
third side = (3x - 6) + 8
The perimeter = 80m and is equal x + (3x - 6) + [(3x - 6) + 8]
x + 3x - 6 + 3x - 6 + 8 = 80
7x - 4 = 80 |+4
7x = 84 |:7
x = 12 m
3x - 6 = 3(12) - 6 = 30 m
(3x - 6) + 8 = 3x + 2 = 3(12) + 2 = 38 m
Answer: 12m, 30m, 38m
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I think its x=2 sorry if im wrong
Step-by-step explanation:
Answer:
x = ¾-a
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x + a = ¾
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Susie gets paid $2,750 every two weeks.
