Question

As an airplane rises, the outside temperature drops 3.6 degrees Fahrenheit for each 1000 feat of elevation gain. Suppose the outside temperature is 65 degrees Fahrenheit on the ground and -43 degrees Fahrenheit at cruising altitude. How high is the plane at cruising altitude?

Answer 1

Answer:

30000 feet

Step-by-step explanation:

temperature on ground level = 65 °F

temperature at cruising altitude = -43 °F

total decrease in temperature = 65 - (- 43) = 65 + 43 = 108 °F

for each 1000 feet elevation temperature drops by 3.6 °F

and we have the total drop of temperature as 108 °F.

so,  Height of plane at cruising altitude = (drop in temperature/ 3.6) X 1000

                                                                 =$\frac{108}{3.6} X 1000$

                                                                 = 30000 feet