Answer:
Number of fish in 2006 = 845 fishes (Approx.)
Step-by-step explanation:
Given;
Number of fish in 2000 = 1,150 fishes
Decreasing rate = 5% per year
Find:
Number of fish in 2006
Computation:
Exponential decay function:
F = P[1-r]ⁿ
Number of year = 2006 - 2000
Number of year = 6 year
Number of fish in 2006 = 1,150[1-5%]⁶
Number of fish in 2006 = 1,150[1-0.05]⁶
Number of fish in 2006 = 1,150[0.95]⁶
Number of fish in 2006 = 1,150[0.735]
Number of fish in 2006 = 845.25
Number of fish in 2006 = 845 fishes (Approx.)
Answer:
27
Step-by-step explanation:
9 crew members complete a job in 3 months
Number of crew members is inversely proportion to construction time :
Let :
Crew members = m
Construction time = t
m α 1 /t
m = k/t
m = 9 ; t = 3
9 = k /3
k = 27
If t = 1 (one month)
m =?
m = k/t
m = 27 / 1
Hence;
m = 27 * 1
m = 27 workers
You have been reading your book for about 7 days
7(10) pages each day + 9 left
70+ 9 = 69
0.71358024691
If you are rounding then the answer would be 0.71
A ratio of 5:7 means out of 12 books, 5 are in one category and 7 are in another. (The “category” isn’t specified in this problem.)
So here we’re STARTING with 36 books; we want to find a ratio that is equal to 5:7 and adds up to 36. Well 36 = 3(12), and so if we multiply each number in the ratio by 3 as well, we might get what we want. Doing that gives us 15:21, which adds up to 36 and is equal to 5:7. Boom, that’s the answer.
P.S. Here’s a question you can think about: why do ratios stay the same when you multiply each number by the same amount? (For example, why is 3:1 the same as 6:2?)
