Answer:
Option B, Spencer did not factor the polynomial completely; 16x^2−1 can be factored over the integers.
Step-by-step explanation:
<u>Step 1: Factor</u>
256x^4y^2−y^2
y^2(256x^4 - 1)
y^2(16x^2 - 1)(16x^2 + 1)
<em>y^2(</em><em>4x + 1)(4x - 1</em><em>)(16x^2 + 1)</em>
<em />
Answer: Option B, Spencer did not factor the polynomial completely; 16x^2−1 can be factored over the integers.
Given:
0.1% of all transactions are fraudulent
99% correct identification whether a transaction is fraudulent or not.
Scanned 5,000,000 transactions.
5,000,000 x 0.1% = 5,000 fraudulent transactions.
For me, there are 5,000 fraudulent transactions. This is based on the 0.1% rather than the 99%. Because the problem clearly states that the 0.1% of ALL transaction is identified as fraudulent. The 99% of the computer program only deals with the correct identification of the transaction as either fraudulent or not. For me, it is not a clear measure of the true number of fraudulent transactions.
Midpoint formula
(x2-x1 / 2) , (y2-y1/ 2)
x = 4-(-2) / 2 = 3
y= -6-2 / 2= -4
midpoint (3, -4)
Answer:
57
Step-by-step explanation:
parentheses first then multiply by 3
