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Anton [14]
3 years ago
5

A scuba diver was at depth of -24 feet with respect to sea level. She swam down 12 more feet to look at a coral reef. Then she s

wam up 9 feet to take a photo of a school of fish before swimming up another 6 feet to join her friend. what was the diver's depth with respect to sea level when she joined her friend?
Mathematics
1 answer:
OLEGan [10]3 years ago
7 0

Answer: The Answer -21

Step-by-step explanation:

DID IT ON EDGE 2020

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If you earn $12 an hour and you work 40 hours a week,<br> how much do you earn a month?
qaws [65]

Answer:

$1,920

Step-by-step explanation:

you multiply 12 by 40. then, assuming a typical month is 4 weeks, you multiply that number by 4.

4 0
3 years ago
Read 2 more answers
Please see attachment
Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }  

Step-by-step explanation:

<u>Step(i)</u>:-

Given function

                       f(x) = \frac{-x}{2x^{2} +1}     ...(i)

Differentiating equation (i) with respective to 'x'

                     f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2}  }   ...(ii)

                    f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  }

Equating Zero

                   f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                 \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                2 x^{2}-1 = 0

               2 x^{2} = 1

             x^{2}  = \frac{1}{2}

             x = \frac{-1}{\sqrt{2} }  , x = \frac{1}{\sqrt{2} }

<u><em>Step(ii):</em></u>-

Again Differentiating equation (ii) with respective to 'x'

f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4}  }

put

      x = \frac{1}{\sqrt{2} }

f^{ll} (x) > 0

The absolute minimum value at   x = \frac{1}{\sqrt{2} }

<u><em>Step(iii):</em></u>-

The value of absolute minimum value

                         f(x) = \frac{-x}{2x^{2} +1}

                       f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}

         on calculation we get

The value of absolute minimum value = - 0.3536      

<u><em>Final answer</em></u>:-

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }    

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It's 38.1

Step-by-step explanation:

I'm not the best at explaining these type of things but I hope this helps you out

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Hey mate here's your answer.....

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Mathematics is a subject where you study more about numbers and daily life applications.

hope its helps you,

follow me....

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Which equation is equivalent to the formula below ​
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C

Step-by-step explanation:

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