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uranmaximum [27]
3 years ago
5

Eileen and her brother Andrew had a bicycle race. Eileen Rode at a speed of 20 ft per second while Andrew Rode at a speed of 15

ft./s. To be fair, Eileen decided to give Andrew a 150 foot Headstart. The race ended in a tie how far away was the finish line from where Eileen started include a graph to support your solution
Mathematics
1 answer:
Julli [10]3 years ago
8 0

Eileen was 600 feet away from the finish line before the race began.

Step-by-step explanation:

Step 1; Eileen rode at a speed of 20 feet per second whereas Andrew rode at a speed of 15 feet per second. So for every second that passes the distance in between decreases by 5 seconds. Assume x is the number of seconds at which the distance in between is 0. The distance in between at the beginning of the race is 150 feet due to the headstart.

Distance between them = Decreasing distance every second × x

150 feet = 5 feet/ second × x

x = 150 feet / 5 feet/second = 30 seconds.

So it takes Eileen 30 seconds to cover the distance between her and Andrew and cross the finishing line at the same time.

Step 2; The race lasted for 30 seconds so we can find the distance Andrew and Eileen traveled by multiplying their speed per second with the total number of seconds.

Distance Andrew traveled = speed per second × total number of seconds

= 15 feet per second × 30 seconds = 450 feet

Distance Eileen traveled = speed per second × total number of seconds

= 20 feet per second × 30 seconds = 600 feet

Graph plot;

The X-axis is time with 5 seconds for each cm

the y-axis is distance with 100 feet for each cm.

Eileen's plot (0,0), (5,100), (10,200), (15,300), (20,400), (25,500), (30,600).

Andrew's plot (0,150), (5,225), (10,300), (15,375), (20,450), (25,525), (30,600).

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Goryan [66]

Answer:

a. Jared and Ali

Step-by-step explanation:

b. Molly make mistake when he/she divide all equation by 4 but left the 8x remain 8x, it should be 2x.

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7 0
3 years ago
write a system of linear equations that has only one solution. solve the system of equations in two ways.
Iteru [2.4K]
X + 5y = 1 . . . . (1)
8x - 2y = 3 . . . .(2)
Solution 1.
From (1), x = 1 - 5y
substituting for x in (2), we have:
8(1 - 5y) - 2y = 3
8 - 40y - 2y = 3
8 - 42y = 3
42y = 5
y = 5/42
x = 1 - 5(5/42) = 1 - 25/42 = 17/42.

Solution 2.
Multiply (1) by 8, to get:
8x + 40y = 8 . . . . . (3)
(3) - (2) = 40y - (-2y) = 8 - 3
42y = 5
y = 5/42
substitute for y into (3), to get:
8x + 40(5/42) = 8
8x + 100/21 = 8
8x = 8 - 100/21 = 68/21
x = (68/21)/8 = 17/42
7 0
3 years ago
Factor completely, the expression: 2x^3-2x^2-12x
muminat
2x^3-2x^2-12x=2x(x^2-x-6)=(*)\\\\------------------------------\\x^2-x-6\\\\a=1;\ b=-1;\ c=-6\\\\\Delta=(-1)^2-4\cdot1\cdot(-6)=1+24=25\\\\\sqrt\Delta=\sqrt{25}=5\\\\x_1=\frac{1-5}{2\cdot1}=\frac{-4}{2}=-2;\ x_2=\frac{1+5}{2\cdot1}=\frac{6}{2}=3\\\\x^2-x-6=(x+2)(x-3)\\\\------------------------------\\\\(*)=2x(x+2)(x-3)
8 0
3 years ago
Given the graph below, find PQ
murzikaleks [220]

Answer:

P=(-5,-1)

Q=(2,-4)

Step-by-step explanation:

hope this helps

7 0
3 years ago
In Class 1, what is the median score? A) 70 B) 70.5 C) 71.5 D) 72
evablogger [386]

Answer:

B)  70.5

Step-by-step explanation:

Median = middle value when the values are placed in order.

If there are two middle values, the median is the mean of those two values.

<u>Class 1</u>

45 46 51 52 53 53 61 63 64 65 66 68 70 <u>70 71</u> 73 76 77 79 81 82 83 84 87 90 92 93 95

There are 28 values in Class 1.

Therefore, there are two middle values: 14th and 15th values

14th value = 70

15th value = 71

\implies \textsf{Median}=\dfrac{70+71}{2}=70.5

3 0
2 years ago
Read 2 more answers
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