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marin [14]
3 years ago
9

Please please please help me!!!!

Mathematics
1 answer:
jeka943 years ago
7 0

X=-1,1,7,-3 p.s. if you plug your equation into math-way you will get the answer just fine on your own try it

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For what value of k will the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent?​
konstantin123 [22]

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Step-by-step explanation:

We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.

If the lines are concurrent, they pass through same point.

Let:

x+2y=0--eq(1)\\ 3x-4y-10=0--eq(2)\\ 5x+ky-7=0--eq(3)

First solving equation 1 and 2 to find values of x and y

From eq(1) we find value of x and put it in eq(2)

From \ eq(1) x+2y=0\\x=-2y\\Put x=-2y \ in \ eq(2)\\3x-4y-10=0\\3(-2y)-4y-10=0 \\-6y-4y=10\\-10y=10\\y=\frac{10}{-10}\\y=-1

After solving we get value of y=-1

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x+2y=0\\x+2(-1)=0\\x-2=0\\x=2

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Now put value of x=2 and y=-1 into eq(3) to find value of k

5x+ky-7=0\\5(2)+k(-1)-7=0\\10-k-7=0\\-k+3=0\\-k=-3\\k=3

So, After solve the equations we get value of k=3

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