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pickupchik [31]
3 years ago
8

Describe what strategy you would use when estimating square roots to the nearest tens place and hundreths place

Mathematics
1 answer:
irina1246 [14]3 years ago
3 0
We assume à priori that we are not using a calculator.

If we require accuracy of nearest tenth or hundredth, we need to know the size of the number we're working with.  It would not be reasonable to estimate the square-root of 284029 to the hundredth place without a calculator.  On the other hand, with one, we can get the exact value and estimation is not required.

The following method should work comfortably well with numbers below hundred, all in the head.  We will take the example of estimating the square-root of 82 to the hundredth, without a calculator (nor pen and paper), using Newton's method.

Newton's method to find square-roots depends on an initial estimate, which is not a problem if we know the multiplication table.

We know that 9*9=81, and 10*10=100, so the square-root of 82 should lie between 9 and 10, but close to 9.  We will use the initial estimate, x0=9.

A better estimate is given by
x1=x0-(x0^2-82)/(2x0)  .................(1)
=9-(81-82)/(18)
=9+1/18
=9.0555...

So to two decimal places, it will be 9.06.
In fact, the exact value is 9.0554, and our estimate was accurate to 3 places of decimal, or almost 4.

If we set x0=9.055 and apply to (1) again, we will get a still better estimate, but the squaring and division will need some help, pen and paper or a calculator.

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8. William got scores of 91, 92, and q3 on three quizzes.
seropon [69]

I am thinking you mean 93 to represent William's scores of 91, 92, and "q3"on three quizzes in Queston 8a

Answer:Average (x)= 92

b.William needs 97 as his third score to get as average of 90

Step-by-step explanation:

a.

The  Average ( x) of the scores  can solved using the Formulae

Average ( x)= Sum of  scores / Number of Scores

Average ( x) = (Score 1 + Score 2 + Score 3) /3

Average (x)= (91, 92, and 93 )/3=276/3 = 92

b) Average ( x) of the scores = Sum of  scores/ Number of Scores

Now  let Score be represented  as  S  such that

Average (x) = (S 1 + S 2 +  S3  )/ 3

90 = 85+ 88+ S/ 3

90 x 3= 85+ 88 + S

270=173+ S

S= 270- 173

S=97

William needs 97 as his third score to get as average of 90

7 0
3 years ago
Help i’m begging plsss
olga_2 [115]

Answer:

x=8

Step-by-step explanation:

Given

AB||CD

\angle ABC = 5x + 50

\angle BCD = 7x + 34

Required

Find x

If AB||CD i.e. If AB is parallel to CD, then

\angle ABC = \angle BCD

Substitute values for ABC and BCD

5x + 50 = 7x + 34

Collect Like Terms

5x - 7x = -50 + 34

-2x = -16

Multiply through by -\frac{1}{2}

-\frac{1}{2} * -2x = -16 * -\frac{1}{2}

\frac{1}{2} * 2x = 16 * \frac{1}{2}

\frac{2x}{2} = \frac{16}{2}

x = \frac{16}{2}

x=8

3 0
3 years ago
7 1/4 boxes weigh total of 66 7/8 what does one box weigh
Ray Of Light [21]

Answer:

68.875 / 7.25 = 9 1/2 pounds

Step-by-step explanation:

6 0
3 years ago
When p2 – 4p is subtracted from p2 + p – 6, the result is 5p-6 To get p – 9, subtract
jeka57 [31]
(p^{2}  + p - 6) - (x) = p - 9

 is what is asked.

So all you need to do is a value that will result to p - 9.

x = (p^{2} + p - 6) - p + 9  To isolate x we just transpose the values from the other side of the equation and do the opposite operation. 

Combine like terms and just copy the terms that do not have similar expressions:

p will cancel out because p - p = 0
-6 and + 9  will come together because they are like terms: -6 + 9 = 3 
p^{2} does not have a pair so it will remain as is. you will be left with:

p^{2}  + 3

Let us check:

   p^{2} + p - 6
-  p^{2} + 0 + 3  
----------------------------
   0 + p - 9    or p -9               
6 0
4 years ago
Read 2 more answers
Just Number 15? Please
Damm [24]
15)
an exterior angle equals the sum of the remote interior angles
<span>so
m<XYT = m<X + m<Z
4x - 25 = x + 15 + 50 - 3x
4x - 25 = -2x + 65
6x = 90
  x = 15

answer
x = 15



</span>
8 0
3 years ago
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