Question

When p2 – 4p is subtracted from p2 + p – 6, the result is 5p-6 To get p – 9, subtract

Answer 1

$(p^{2} + p - 6) - (x) = p - 9$ is what is asked.

So all you need to do is a value that will result to p - 9.

x = $(p^{2} + p - 6) - p + 9$  To isolate x we just transpose the values from the other side of the equation and do the opposite operation. 

Combine like terms and just copy the terms that do not have similar expressions:

p will cancel out because p - p = 0
-6 and + 9  will come together because they are like terms: -6 + 9 = 3 
$p^{2}$ does not have a pair so it will remain as is. you will be left with:

$p^{2} + 3$

Let us check:

   $p^{2} + p - 6$
-  $p^{2} + 0 + 3$  
----------------------------
   $0 + p - 9$    or $p -9$               

Answer 2

Answer:

We have to subtract $p^2+3$ from the given expression to obtain a difference of $p-9$

Step-by-step explanation:

We are given the following information in the question:

We are given an expression:

$p^2 + p -6$

We subtract $p^2 - 4p$ from the given expression.

$p^2 + p -6 - (p^2 - 4p)\\= (p^2 - p^2) + (p + 4p)-6\\=5p - 6$

Now, we want to obtain the difference as $p-9$

Let x be the expression we subtract from the given expression, then we can write:

$p^2 + p -6 - x = p-9\\p^2 +p -6-(p-9) = x\\x = p^2+(p-p)+(-6+9)\\x = p^2+3$

Thus, we have to subtract $p^2+3$ from the given expression to obtain a difference of $p-9$