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UkoKoshka [18]
3 years ago
11

What is the area of this shape?

Mathematics
2 answers:
maks197457 [2]3 years ago
7 0
Hope this helps u...!!
The answer u have written before seems to be the right answer...!!!

Hunter-Best [27]3 years ago
5 0

Surface Area of the square = 8 x 8 = 64 cm²

Surface Area of the 4 triangle = 4 x [ 1/2 x 8 x 14] 
Surface Area of the 4 triangle = 4 x [ 56] 
Surface Area of the 4 triangle = 224 cm²

Total Surface Area = 64 + 224 = 288 cm²

Answer:  288 cm²

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15,30, 60,... Find the 6th term.​
kolbaska11 [484]

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15, 30, 60, 120, 240, <u>480</u>.

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You multiply the numbers by 2 to get to the next number.

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Answer:

(Base)Height

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3 0
3 years ago
Simplify: |2-5|-(12 ÷4-1)^2
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5 0
4 years ago
A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple. How many ways are there to choose:(
Volgvan

Answer:

The number of ways of selecting of n items form r different items =^{(n+r-1)}C_{(r-1)}

A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple.

A) How many ways are there to choose 32 candies?

So, n = no. of items = 32

r = no. of types of items = 5

So, No. of ways to choose 32 candies = ^{(32+5-1)}C_{(5-1)}

                                                               = ^{36}C_{4}

                                                                 = \frac{36!}{4!(36-4)!}

                                                                 = 58905

So, No. of ways to choose 32 candies is 58905

B)32 candies with at least a piece of each flavor?

Out of 32 you choose 5 candies of different types

So, Remaining candies = 32 - 5 = 27

So, No. of ways to choose 27 candies = ^{(27+5-1)}C_{(5-1)}

                                                               = ^{31}C_{4}

                                                                 = \frac{31!}{4!(31-4)!}

                                                                 = 31465

So, No. of ways to choose 32 candies with at least a piece of each flavor is 31465

C) 32 candies with at least 4 cherry and at least 6 lemon?

So, you already choose 6+4= 10

So, remaining candies = 32-10 = 22

So, No. of ways to choose 22 candies = ^{(22+5-1)}C_{(5-1)}

                                                               = ^{26}C_{4}

                                                                 = \frac{26!}{4!(26-4)!}

                                                                 = 14950

Hence No. of ways to choose 32 candies with at least 4 cherry and at least 6 lemon is 14950

8 0
4 years ago
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