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Rina8888 [55]
3 years ago
12

Last year, 7600 athletes finished a marathon in Lakeside, This year there were 6156 athletes finishing. What is the percent decr

ease in the number of finishers?
Mathematics
2 answers:
erastova [34]3 years ago
8 0

Answer:

19.00 % decrease

Step-by-step explanation:

Change = Final – initial

% change = (Final – Initial)/Initial × 100 %

% Change = (6156 - 7600)/7600 × 100 %

% Change = -1444/7600 × 100%

% Change = -19.00 %

NemiM [27]3 years ago
7 0

Answer:

6156/7600=0.81   1-0.81= 0.19   THERE IS A 0.19% decrease in the number of finishers

Brainliest?

Step-by-step explanation:


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Answer:

$1.21\times 10^{7} per minute.

Step-by-step explanation:  

We have been given that a certain animated movie earned $1.1\times10^{9} in revenues at the box office. The movie lasts 9.1\times10^{1} minutes.

To find the revenue earned per minute of the movie we will will divide 1.1\times10^{9} by 9.1\times10^{1}.

\text{The revenue earned per minute by the movie}=\frac{1.1*10^{9}}{9.1*10^{1}}  

Using quotient rule of exponents we will get,

\text{The revenue earned per minute by the movie}=\frac{1.1}{9.1}*10^{(9-1)}

\text{The revenue earned per minute by the movie}=\frac{1.1}{9.1}*10^{8}

\text{The revenue earned per minute by the movie}=0.1208791208791209\times 10^{8}

We can write 0.1208791208791209 as 1.208791208791209\times10^{-1}.

\text{The revenue earned per minute by the movie}=1.208791208791209\times 10^{-1} \times 10^{8}

Using product rule of exponents we will get,    

\text{The revenue earned per minute by the movie}=1.208791208791209\times 10^{-1+8}    

\text{The revenue earned per minute by the movie}=1.208791208791209\times 10^{7}

Upon rounding our answer to two decimal places we will get,

\text{The revenue earned per minute by the movie}=1.21\times 10^{7}      

Therefore, the movie had earned a revenue of $1.21\times 10^{7} per minute.

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