We have calculated a 95% confidence interval and would prefer for our next confidence interval to have a smaller margin of error
1 answer:
You might be interested in
Answer:
there is ur Answer
hope that will help you.
nice time
Answer:
WU = (14√13)/13 ≈ 6.6564
Step-by-step explanation:
Call the incenter of ∆KWU point A. Call the center of circle ω2 point B.
Then ∠KWA has half the measure of arc WA. ∠AWU is congruent to ∠KWA, so also has half the arc measure. That is, ∠KWU has the same measure as arc WA and ∠KBW.
KB is a perpendicular bisector of chord WU, so ∆KWB is a right triangle, of which WU is twice the altitude to base KB.
The length of KB can be found several ways. One of them is to use the Pythagorean theorem:
KB² = KW² +WB² = 4² +6² = 52
KB = √52 = 2√13
The area of triangle KWB is ...
area ∆KWB = (1/2)KW·WB = (1/2)(4)(6) = 12 . . . . square units
Using KB as the base in the area calculation, we have ...
area ∆KWB = (1/2)(KB)(WU/2)
12 = KB·WU/4
WU = 48/KB = 48/(2√13) = 24/√13
WU = (24√13)/13 ≈ 6.6564
Answer:
The lengths of the bases are 9 inches and 15 inches.
Step-by-step explanation:
The area of trapezoid is
Given that the height of a trapezoid is 8 in. and its area is 96 in².
Assume the bases of the trapezoid be b₁ and b₂.
Since one base of the trapezoid 6 in. longer than the other.
Let, b₁=b₂+6
The area of the trapezoid is
in²
in²
in²
According to the problem,
[ Multiplying
]
Then,
=9+6
=15 in
The lengths of the bases are 9 inches and 15 inches.