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olasank [31]
3 years ago
6

We have calculated a 95% confidence interval and would prefer for our next confidence interval to have a smaller margin of error

without losing any confidence. In order to do this, we can ________.
I. change the z* value to a smaller number.
II. take a larger sample.
III. take a smaller sample.
Which is the correct answer from above? There can be more than one.
Mathematics
1 answer:
stepladder [879]3 years ago
3 0

Answer:

asdfghjkl

Step-by-step explanation:

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Joan is building a sandbox in the shape of a regular pentagon. The perimeter of the pentagon is 35y4 – 65x3 inches. What is the
PIT_PIT [208]
From the choices above the answer would be: D 7y^4-13x^3 inches
8 0
4 years ago
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What is the volume of the box if it is scaled down by a factor of 1/10?
Natalka [10]

Answer:

8.4in²

Step-by-step explanation:

We are given the dimensions of a box as :

7in = Height

6in = Length

2in = Width

The volume of a box = Length × Width × Height

Volume of a box = 7in × 6in × 2in

= 84in²

We are also told in the question to find the volume of the box if it is scaled down by a factor of 1/10

Hence,the new volume = 84in² × 1/10

= 8.4in²

Therefore, the volume of the box if it is scaled down by a factor of 1/10 is 8.4in²

8 0
4 years ago
Solve the following exponential equations.<br> 2(4^x )+ 4^(x+1 )= 342
Cloud [144]

Answer:

  x ≈ 2.91644500708

Step-by-step explanation:

The equation can be simplified to ...

  2(4^x) +4(4^x) = 342

  6(4^x) = 342

  4^x = 57

Taking logarithms, we get ...

  x = log₄(57) = log(57)/log(4)

  x ≈ 2.91644500708

5 0
3 years ago
M is the midpoint of , cm = 2x + 3, and md = 3x – 6. what is cd? answer
wlad13 [49]
<span>If M is the midpoint of CD, CM = 2x+3 and MD = 3x-6, then:

MD = CM
3x - 6 = </span>2x + 3
3x - 2x = 3 + 6
x = 9

CM = 2x+3 = 2*9+3  18+3 = 21
MD = CM = 21
CD = CM + MD = 21 + 21 = 42
7 0
4 years ago
Of the following points, name all that lie on the same vertical line?
Masteriza [31]

Answer:

(-2,-6) (6,2)

Step-by-step explanation:

4 0
3 years ago
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