Answer:
7 and 1
Step-by-step explanation:
Let the numbers be a and b.
<u>A positive number is 7 times another number:</u>
<u>If 3 is added to both the numbers then one of the new number becomes 5 by 2 times the other new number:</u>
<u>To solve this we substitute </u><u>a</u><u> with </u><u>7b</u><u> in the second equation:</u>
- 7b + 3 = 5/2 × (b +3) ⇒ multiplying both sides by 2
- 14b + 6 = 5b + 15 ⇒ collecting like terms
- 14b - 5b = 15 - 6
- 9b = 9
- b = 1 ⇒ solved for b
<u>Then, finding a:</u>
- a= 7b
- a=7*1
- a= 7 ⇒ solved for a
<u>So the numbers are</u> 7 and 1
Answer:
49
Step-by-step explanation:
∆ABC~ ∆XYZ
AB= 11 that is half of XY = 22
therefore XZ/2 = AC (base) = 32/2 = 16
and YZ /2 = BC(hypotenuse) = 44/2 = 22
(a= 11, b= 16, c= 22)
perimeter of a triangle
P = a+b+c
P= 11+16+22= 49
Answer:
Answer is 3/4
Step-by-step explanation:
Answer:
I think it's C
Step-by-step explanation:
