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liberstina [14]
3 years ago
7

Further, Boris must also take into consideration the chicken calorie specifications which, as you know, are imposed by customers

and competitors. The target for the chicken calorie content is 475 calories---with a tolerance level of 50 calories in each direction. The upper control limit of the X-bar chart is: (Please round up) a) More than 520 calories but less than or equal to 540 calories. b) More than 540 calories but less than or equal to 560 calories. c) More than 560 calories but less than or equal to 580 calories. d) More than 580 calories but less than or equal to 600 calories. e) None of the above.The lower control limit of the X-bar chart is:a) More than 415 calories but less than or equal to 430 calories.b) More than 430 calories but less than or equal to 445 calories.c) More than 445 calories but less than or equal to 460 calories.d) More than 460 calories but less than or equal to 475 calories.The process capability index, Cp, is:a) Negative.b)Less than 1.c)More than 1 but less than 1.3d)More than 1 but less than 1.4.e)None of the above.The process capability index, Cpk, is:a) Negative.b) Less than 1.c) More than 1 but less than 1.05d) More than 1 but less than 1.08e) None of the above.
Mathematics
1 answer:
PolarNik [594]3 years ago
8 0

Answer:

a, a, b,b

Step-by-step explanation:

Upper bound: 475+50= 525

lower bound: 475-50= 425

Cp= (Upper bound-lower bound)/ 6σ

Cp= (525-525)/ (6× 50)

Cp= 0.33

Cpk is minimum of two following values: (Upper bound-mean)/ 3σ, (mean -lower bound)/ 3σ

Cpk in this case is: Min (0.33,0.33)

The Cp and Cpk values are  calculated from the actual process values. Here target Cp and Cpk value is 0.33

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PLEASE ALSO EXPLAIN HOW TO SOLVE THIS. 20 POINTS
eimsori [14]
B.) Hibiscus Street 

The key thing to remember is the slope of the lines. The equation for a line in slope intercept form is
y = ax + b
where
a = slope
b = y intercept

So the equation for Oak Street is y = 2/3x - 7. So it's slope is 2/3. And any street that has the same slope will be given a tree name. And any street that's perpendicular will be given a flower name. You can determine is a line is perpendicular if it has a slope that's the negative reciprocal. So a street that's perpendicular to Oak street will have a slope of -3/2.

Now you've just been given the equation to a new street that's y = -3/2x - 2. Since the slope is -3/2 and Oak street has a slope of 2/3, the new street is perpendicular to Oak street. And given the naming scheme, that means that the new street will have the name of a flower. So let's look at the available street names and pick a flower.
<span>
A.) Weeping Willow Street
* Nope a Weeping Willow is a tree. So this name won't work.
 
B.) Hibiscus Street 
* Yes. A Hibiscus is a flower, so this name is suitable.

C.) Oak Street 
* Nope. Not only is this a tree instead of a flower, but there's already an Oak street. So bad choice.

D.) Panther Street
* Nope, this is an animal, not a flower. Bad choice.

</span>
6 0
3 years ago
Need help fast please! Factor by grouping. 6x³ + 24x² -7x -28 =
olchik [2.2K]

Answer:

(x+4)(6x^2 - 7)

Step-by-step explanation:

Focus on the first 2 terms first and on the second 2 terms last:

6x^3 + 24x^2 = 6x^2(x+4)

-7x-28 = -7(x+4)

We see that the factor (x+4) is common to both pairs:  common to the first 2 terms and common to the last 2 terms.

Thus,

6x³ + 24x² -7x -28 = (x+4)(6x^2 - 7(x+4)

Factoring out x+4, we get (6x^2 - 7), and so 6x³ + 24x² -7x -28 in factored form is (x+4)(6x^2 - 7).

5 0
4 years ago
I need help with this!!<br>Please..<br>​
vagabundo [1.1K]

Answer:

What's the previous problem

Step-by-step explanation:

7 0
3 years ago
Question 2 - Signal and System Properties. State whether each of the statements is true or false. Note that a statement is true
gregori [183]

Answer:

  (a) true

  (b) true

  (c) false; {y = x, t < 1; y = 2x, t ≥ 1}

  (d) false; y = 200x for .005 < |x| < 1

Step-by-step explanation:

(a)  "s(t) is periodic with period T" means s(t) = s(t+nT) for any integer n. Since values of n may be of the form n = 2m for any integer m, then this also means ...

  s(t) = s(t +2mt) = s(t +m(2T)) . . . for any integer m

This equation matches the form of a function periodic with period 2T.

__

(b) A system being linear means the output for the sum of two inputs is the sum of the outputs from the separate inputs:

  s(a) +s(b) = s(a+b) . . . . definition of linear function

Then if a=b, you have

  2s(a) = s(2a)

__

(c) The output from a time-shifted input will only be the time-shifted output of the unshifted input if the system is time-invariant. The problem conditions here don't require that. A system can be "linear continuous time" and still be time-varying.

__

(d) A restriction on an input magnitude does not mean the same restriction applies to the output magnitude. The system may have gain, for example.

6 0
4 years ago
2xy-3x+4xy+8x simplified?
photoshop1234 [79]
2xy - 3x + 4xy + 8x
(Try to bring xy species together & x-type together)
2xy+4xy + 8x-3x
6xy + 5x

So, Your Answer would be 6xy + 5x

Hope this helps!
3 0
3 years ago
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