Answer: The required polynomial of lowest degree is 
Step-by-step explanation: We are given to find a polynomial function of lowest degree with real coefficients having zeroes of 2 and -5i.
We know that
if x = a is a zero of a real polynomial function p(x), then (x - a) is a factor of the polynomial p(x).
So, according to the given information, (x - 2) and ( x + 5i) are the factors of the given polynomial.
Also, we know that complex zeroes occur in conjugate pairs, so 5i will also be a zero of the given polynomial.
This implies that (x - 5i) is also a factor of the given polynomial.
Therefore, the polynomial of lowest degree (three) with real coefficients having zeroes of 2 and -5i is given by
Thus, the required polynomial of lowest degree is
Our aim is to calculate the Radius so that to use the formula related to the area of a segment of a circle, that is: Aire of segment = Ф.R²/2
Let o be the center of the circle, AB the chord of 8 in subtending the arc f120°
Let OH be the altitude of triangle AOB. We know that a chord perpendicular to a radius bisects the chord in the middle. Hence AH = HB = 4 in
The triangle HOB is a semi equilateral triangle, so OH (facing 30°)=1/2 R. Now Pythagoras: OB² = OH² + 4²==> R² = (R/2)² + 16
R² = R²/4 +16. Solve for R ==> R =8/√3
OB² = OH² +
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Answer: D) The y intercept is (0,1)</h3>
This can be confirmed by plugging x = 0 into the function to find that...
y = (1/2)^x
y = (1/2)^0
y = 1
Recall that any nonzero value to the 0th power leads to 1. So we can say x^0 = 1 as long as x is not zero.
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Extra info (optional section):
- We can rule out choice A because negative x values work in the domain. For instance, if x = -1, then it leads to y = (1/2)^x = (1/2)^(-1) = 2. The negative exponent will apply the reciprocal operation to the base fraction.
- Choice B can also be ruled out because the range is y > 0. Or you could note that it is possible to get positive y values smaller than 1/2. Try x = 2 and you'll see it leads to y = 1/4 which is not greater than 1/2.
- Choice C is false as well. The function f(x) = (1/2)^x is decreasing throughout the domain. A graph visually would show this due to it going downhill when moving from left to right. A table of values is a non-visual way to see we have a decreasing function. The table would show that y decreases when x increases.
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