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3 years ago

7

Help .................................................

2 answers:

kati45 [8]3 years ago

5 0

AC-AB=BC
53-4x-6=2x+5
42=6x
x=7
BC=2x+5=2(7)+5=19

Ksenya-84 [330]3 years ago

4 0

The correct answer is 19 because x=7
Hope this helped :)

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2 years ago

If a=8, b=6 and c=2 what is the value of: 2ac/b

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3 years ago

baherus [9]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = $\frac{\sqrt3}{2}$

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

$\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}$

Proof LHS → RHS:

LHS cos 165

Double-Angle: cos (2 · 165) = 2 cos² 165 - 1

⇒ cos 330 = 2 cos² 165 - 1

⇒ 2 cos² 165 = cos 330 + 1

Given: $2 \cos^2 165 = \dfrac{\sqrt3}{2} + 1$

$\rightarrow 2 \cos^2 165 = \dfrac{\sqrt3}{2} + \dfrac{2}{2}$

Divide by 2: $\cos^2 165 = \dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \dfrac{2\sqrt3+4}{8}$

Square root: $\sqrt{\cos^2 165} = \sqrt{\dfrac{4+2\sqrt3}{8}}$

Scratchwork: $\cos^2 165 = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2$

$\rightarrow \cos 165 = \pm \dfrac{\sqrt3+1}{2\sqrt2}$

Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

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LHS = RHS $\checkmark$

4 0

3 years ago

Rewrite <img src="https://tex.z-dn.net/?f=%5Cfrac%7B200x%20-%20300%7D%7Bx%7D" id="TexFormula1" title="\frac{200x - 300}{x}" alt=

lord [1]

Answer:

We can rewrite this as $\frac{200x}{x} + \frac{-300}{x}$ .

$\frac{200x}{x}$ simplifies to 200 after eliminating x from the numerator and denominator and $\frac{-300}{x}$ becomes $-\frac{300}{x}$ so the final answer is $200 - \frac{300}{x}$ .

6 0

3 years ago