Using the equation y = 2x – 3, what would the input need to be for an output of 7?

Mathematics

2 answers:

Keith_Richards [23]3 years ago

8 0

Answer:

Step-by-step explanation:

We have an equation and are asked to find the input of x when y = 7.

The output = y = 7

The input = x

7 = 2x - 3

2x - 3 = 7

We need to find a number that multiplied by 2 which then is subtracted by 3 equals 7. We can use the backwards method to solve our answer.

2x - 3 = 7

7 + 3 = 2x

10 = 2x

Solve for x by dividing 2 from both sides :

x = 5.

Therefore, you would need an input of 5 to get 7 as the output.

Proof :

2(5) - 3 = 7

10 - 3 = 7

kari74 [83]3 years ago

4 0

Answer:

x = 5

Step-by-step explanation:

Remark

This is a fancy way of asking you what is the value of x when y = 7

Equation

7 = 2x - 3

Solution

7 = 2x - 3 Add 3 to both sides

7 + 3 = 2x Combine the left.

10 = 2x Divide by 2

2x/2 = 10/2

x = 5

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Calvin deposits $400 in a savings account that accrues 5% interest compounded monthly. after c years, calvin has $658.80. makayl

vodomira [7]

You will need a special formula to compute this.
Years = log (total/principal) / [n * log * (1 + rate / n)]

Part A) Calvin $400 5% monthly 658.80 Time = ?
Monthly compounding "n" = 12
Years = log(658.80/400) / [12 * log(1+ (.05/n))
Years = log ( 1.647 ) / (12 * log ( 1.0041666667 )
Years = 0.21669359917 / 12 * 0.0018058008777
Years = 0.21669359917 / 0.0216696105 
Years = 9.999884362 


Part B) Makayla 300 6% quarterly 613.04Time=?
Quarterly compounding
n = 4
Years = log (total/principal) / [n * log * (1 + rate / n)]
Years = log (613.04/300) / [4 * log (1 + .06/4)]
Years = log ( 2.0434666667 ) / 4 * log (1.015)
Years = 0.31036755784 / 4 * 0.0064660422492
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Years = 11.9999044949 

So, the difference is roughly 3 years.