HELP NOW!!!! BRANLIEST AND 20 POINTS

My bill at a restaurant was $25 even and I want to tip 20% how much would I pay

Nookie1986 [14]

Answer:

$30

Step-by-step explanation:

20% of 25 = 5

c = 25 + 5

25/100 = 0.25*20

7 0

4 years ago

Can somebody please help me with this

Paul [167]

∠PYG = 137°

Step-by-step explanation:

We know that a straight line is equal to 180°, so by looking at the image we can tell that if we added both of these angles together they would be equal to the straight line.

We can make an equation by adding these two angles together and setting them equal to 180.

$2p+153+6p+91=180$

We can combine like terms.

$8p+244=180$

Subtract 244 from both sides.

$8p=-64$

Divide.

p = -8

Now that we have found what p is equal to, we can plug it in to find the measure of ∠PYG.

$2*-8+153$

= 137

~

If you wanted to double check this answer, we can plug in -8 for p on the other side and make sure both would be equal to 180.

Like this...

$6*-8+91$

= 43

And we know that...

137 + 43 = 180

~

So...

∠PYG = 137°

∠HYG = 43°

4 0

3 years ago

When jumping, a flea rapidly extends its legs, reaching a takeoff speed of 1.0 m/s over a distance of 0.50 mm . part a what is t

pshichka [43]

The flea's acceleration is 1,000 m/s².

<h3>Further explanation</h3>

The problem we overlook this time is about uniformly accelerated motion.

The list of variables to be considered is as follows.

$\boxed{u \ or \ v_i = initial \ velocity}$

$\boxed{u \ or \ v_t \ or \ v_i = terminal \ or \ final \ velocity}$

$\boxed{a = acceleration \ (constant)}$

$\boxed{d = distance \ travelled}$

Given that a take-off speed of 1.0 m/s over a distance of 0.50 mm.

The initial speed was zero from rest. It was asked about flea's acceleration when she extends her legs.

The formula we follow for this problem are as follows:

$\boxed{ \ v^2 = u^2 + 2ad \ }$

a = acceleration (in m/s²)
u = initial velocity = 0 m/s
v = take off speed = 1.0 m/s
d = distance travelled = 0.50 mm

Converted 0.50 mm to meters: $\boxed{0.50 \ mm = 0.50 \times 10^{-3} \ m = 5.0 \times 10^{-4} \ m}$

Steps:

We set the formula so that the acceleration becomes the subject.

$\boxed{ \ v^2 = u^2 + 2ad \ }$

$\boxed{ \ v^2 - u^2 = 2ad \ }$

$\boxed{ \ 2ad = v^2 - u^2 \ }$

$\boxed{ \ a = \frac{v^2 - u^2}{2d} \ }$

Substitute all data into equations.

$\boxed{ \ a = \frac{(1.0)^2 - (0)^2}{2(5.0 \times 10^{-4})} \ }$

$\boxed{ \ a = \frac{1}{10 \times 10^{-4}} \ }$

$\boxed{ \ a = \frac{1}{1 \times 10^{-3}} \ }$

$\boxed{ \ a = 1 \times 10^{3}\ = 1,000 \ m/s^2 \ }$

We get the flea's acceleration, i.e., 1,000 m/s².

<h3>Learn more</h3>

About scientific notation brainly.com/question/7263463
Finding the mass of substance brainly.com/question/4053884
Converting in cubic brainly.com/question/1446243

Keywords: flea, when jumping, rapidly extends its legs, take-off speed, initial velocity, distance, acceleration, uniformly accelerated motion, convert