A starting lineup in basketball consists of two guards, two forwards, and a center. (a) a certain college team has on its roster
four centers, five guards, three forwards, and one individual (x) who can play either guard or forward. how many different starting lineups can be created? [hint: consider lineups without x, then lineups with x as guard, then lineups with x as forward.] 240 lineups
You need to first add 5 to the -5. Even though the - is a subtraction sign, you can still count it as a subtraction sign. In order to balance it out again, so you add the 5 to the 16. 16+5=21, so the equation would be -3x=21. To get x by itself, you divide by -3. So, -3x/-3 and 21/-3. That gets rid of the -3, and you get a -7 as an answer.