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almond37 [142]
3 years ago
14

Evaluate and simplify sin (-15º).

Mathematics
1 answer:
olga55 [171]3 years ago
7 0
Note:

sin(-θ) = -sinθ

sin(-15°) = -sin15°              Use a calculator

sin(-15°) = -sin15°  = -0.2588

sin(-15°) = -0.2588
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What is the range of a function y=|x+3| -3 if the domain is x€R
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Answer:

y ≥−3

Step-by-step explanation:

1 By inspecting the graph, the range is:

y\ge -3y≥−3

Done

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What is 5(2 + x) = 5 ?
Alex787 [66]

5(2+x)=5

or, 10+5x=5

or, 5x= -5

or, x= -1

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Please help me with this question :(
nalin [4]

Answer: See below

Step-by-step explanation:

4 parts of the whole are shaded, and there are a total of 10 parts

So the fraction is: 4/10

Simplifying by dividing both the numerator and denominator by 2 would give <em>2/5</em>

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Two cities are 45 miles apart. Two trains, with speeds of 70 mph and 60 mph, leave the two cities at the same time so that one i
KATRIN_1 [288]

The distance between the trains is changing at the rate of (70 -60) = 10 mph. They will be in the same place (45 mi)/(10 mi/h) = 4.5 hours after they leave their respective cities. They will be 10 miles apart both 1 hour before that time and one hour after that time.

The trains will be 10 miles apart 3.5 hours after leaving.

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3 years ago
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A cooling tower for a nuclear reactor is to be constructed in the shape of a hyperboloid of one sheet. The diameter at the base
timurjin [86]

Answer:

Step-by-step explanation:

Equation for a hyperboloid of one sheet, with center at the origen and axis along z-axis is:

(x/a)²  +  (y/b)²   -  (z/c)²  =  1                         (1)

We have to find a , b, and c

We can express equation (1)

(x/a)²  +  (y/b)²    =  (z/c)² + 1                 (2)

Now if we cut the hyperboloid with planes parallel to xy plane we get for  z = k       ( K = 1 , 2 , 3  and so on ) circles of different radius

(x/a)²  +  (y/b)²    =  (k/c)² + 1

at z = k = 0 at the base of the hyperboloid  d = 300   or r = 150 m

we have

(x/a)²  +  (y/b)²   = 1      

x²  +  y²   =   a²                a² = (150)²       a = b = 150

and    x²  +  y²  = (150)²

Now the other condition is at 200 m above the base d = 500 m   r = 250 m  minimum diameter then in equation (2)  we have:

(x/a)²  +  (y/b)²    =  (z/c)² + 1        

(1/a)² [ x² + y² ]  = (z/c)² + 1  

but   x²  +  y²  = r²    and in this case   r  =  250 m  then

(250)²/(150)²   =  (z/c)² + 1    ⇒ (62500/ 22500)  =  (200/c)² + 1

2,78  =  40000/c² + 1

2.78c²  =  40000  + c²

1.78c² = 40000

c²  =  40000/1.78

c²  = 22471.91

c = 149,91

Then we finally have the equation:

x²/(150)²   + y² /(150)² - z²/149,91  = 1

7 0
3 years ago
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