A. 3/5 * 60 minutes = 180/5 = 36 minutes
b. (3/4)/12 = 3/(4*12) = 3/48 = 1/16 cup
c. (5 1/3) / (2/3) = (16/3) / (2/3) = 16/3 * 3/2 = 48/6 = 8 days
d. 137/16 = 8.5625 pounds
Alright so I'm coming up with this on the fly; you have the first six letters (a,b,c,d,e,f) and 0-9 and your ten numbers. calculate the amount of possible combinations for the letters by simply writing them down.
ab, ac, ad, ae, a f- five
bc, bd , be, bf- four
cd, ce, cf- three
de, df- two
ef,- one.
adding these all together gets a total of 15 for the letters. now the numbers
01, 02, 03, 04, 05, 06, 07, 08, 09- nine
12, 13, 14, 15, 16, 17, 18, 19- eight
23, 24, 25, 26, 27, 28, 29- seven
34, 35, 36, 37, 38, 39- six
45, 46, 47, 48, 49- five
56, 57, 58, 59- four
67, 68, 69- three
78, 79- two
89- one
added together with a total of 45 combinations.
alright so, 45 different number combinations and 15 letter combinations. multiplying 15 by 45 should tell you the total possible combinations for a two letter and two number serial-number
Answer:
a. $20.45
b. $24.55
c. $4.55
Step-by-step explanation:
In this question, we are asked to calculate the cost price and profit or loss selling a pair of shoes.
we proceed as follows
Firstly, we want to find the cost price given the selling price and the mark up percentage.
mathematically;
profit =( selling price - cost price)/cost price * 100%
here our profit is 120% with the cost price being $45. we plug these values
120 = 45-cp/cp * 100%
120cp = 100(45-cp)
120cp = 4500 -100cp
220cp = 4500
cp = 4500/220 = $20.45
His profit is selling price - cost price = 45 - 20.45 = $24.55
His profit selling same shoe for $25 is 25-20.45 = $4.55
