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Ray Of Light [21]
3 years ago
14

The coefficient of xkyn-k in the expansion of (x+y)n equals (n/k) true or false

Mathematics
2 answers:
dexar [7]3 years ago
7 0

Answer:

The correct option is 1. The given statement is true.

Step-by-step explanation:

The binomial expansion is defined as

(x+y)^n=^nC_0x^{n-0}y^{1}+^nC_{1}x^{n-1}y^{2}+....+^nC_{n-1}x^{1}y^{n-1}+^nC_nx^{0}y^{n}

The rth term in a binomial expansion is defined as

\text{rth term}=^nC_rx^{n-r}y^{r}

Let the coefficient of x^ky^{n-k} be A. The power of x is k and the power of y is n-k. It means

k=n-r

n-k=r

The coefficient of x^ky^{n-k} is

^nC_{n-k}=\binom{n}{n-k}

Using the property of combination,

^nC_{n-r}=^nC_r

^nC_{n-k}=^nC_{k}=\binom{n}{k}

The coefficient of x^ky^{n-k} is \binom{n}{k}. Therefore the given statement is true.

RUDIKE [14]3 years ago
6 0
The answer to your question is
TRUE -Apex
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