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anastassius [24]
3 years ago
8

A pet store has 26 rabbits and hamsters. The number of rabbits is two more than double the number of hamsters. Which equation be

low can be used to solve for the number of rabbits, r?
A) 2r + 26 = 4r - 2

B) 26 + r = 2r - 2

C) 2r + 26 = r - 2

D) 26 - r = 2r + 2
Mathematics
1 answer:
Ivenika [448]3 years ago
6 0

Answer:

correct choice is D

Step-by-step explanation:

Let r be the number of hamsters. If the number of rabbits is two more than double the number of hamsters, then the number of rabbits is 2r+2.

A pet store has 26 rabbits and hamsters. When you subtract the number of hamsters from the total number of rabbits and hamsters, then you'll get the number of rabbits:

26 - r = 2r + 2.

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The table shows the input and output of a function Table(input:3,4,6,11. Output:5,7,11,21) write an equation, in function nation
Anni [7]

f(x) = 2x - 1

To obtain a function we require values of x for x = 3, 4, 5 , 6, .....

The output appears to increase in steps of 2

3 → 5

4 → 7

5 → 9

6 → 11

Looking at the consecutive values of y we should see that these are twice the corresponding value of x subtract 1

f(x) = 2x - 1 ← is a possible function

checking the values for x in the input


f(3) =(2 × 3 ) - 1 = 5

f(4) = (2 × 4 ) - 1 = 7

f(6) = (2 × 6 ) - 1 = 11

f(11) = (2 × 11 ) - 1 = 21




6 0
3 years ago
Compute delta y/delta x for the interval [2,5], where y = 4x - 9.
Kamila [148]
We have to compute: Δ y / Δ x.
The interval is [ 2, 5 ] and y = 4 x - 9.
y 1 = 4 · 2 - 9 = 8 - 9 = - 1
y 2 = 4 · 5 - 9 = 20 - 9 = 11
Δ y / Δ x = ( y 2 - y 1 ) / ( x 2 - x 1 ) =
= ( 11 - ( - 1 ) ) / ( 5 - 2 ) = ( 11 + 1 ) / 3 = 12 / 3 = 4
Answer:
Δ y / Δ x = 4

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A boy is 6 years older than his sister. In three years time he will be twice her age. What
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18-6=12

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Bishon needs to sell at least 0.3 of his collection of sports cards to
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I need to use the Pythagorean Theorem to find X. I don’t know how to do that!!
frutty [35]

Answer:

17) x=8

18) x=\sqrt{189} or x= 3\sqrt{21}

Step-by-step explanation:

So the rule is a^{2} +b^{2} =c^{2}, "c" being the hypothenuse, or the long line that is opposite to the right angle.

17) We know that both values of x are equal to each other, which makes everything 10x easier!

                                               x^{2} +x^{2} =(8\sqrt{2})  ^{2}

(by the way we know the x values are our a and b values because they are legs! the way I like to remember the legs is that they are connected to the right angle box, and therefore support the hypothenuse)

<em>simplify</em> (╥︣﹏╥)    

                                                2x^2=8^2(\sqrt{2} )^{2}  

                                                  2x^2=64(2)

                                                   2x^2=128    

                                                  x^{2}= 128/2  

                                                     x^{2} =64

                                                        x=8      

18) Just pretend that the flipped triangle doesn't exist. It's parallel to the other triangle with values on it, and basically servers no purpose other than being parallel to the sister triangle :)

Anyways, since we know the hypothenuse (15) but we don't know one of our leg values (x), we're going to change our equation a bit!

                                                    c^{2} - b^{2} = a^{2}

It doesn't matter if you put the one leg value in a or b, just as long as you stick to that same equation you started with the entire time!

                                                   15^{2} -6^{2} =x^{2}

                                                   225-36=x^{2}  

                                                     x^{2} =189

                                               x=\sqrt{189}=3\sqrt{21}

        The more you do these, the easier they'll get, so don't worry!

                           

4 0
3 years ago
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