This is tricky
lets try substituting y = √)6x - 9)

√(6 - y) + √(6x + y) = √6

squaring both sides:-

6 - y + 6 + y - 2√(6 - y)(6 + y) = 6
12 - 2√(6 - y)(6 + y) = 6
√(6 - y)(6 + y) = (6-12) / -2 = 3
Squaring both sides:-
(6 - y)(6 + y) = 9
36 - y^2 = 9
y^2 = 27
y = +/-√27

√(6x - 9) = +/- 27

6x - 9 = 729

x = 738/6 = 123

This cannot be a solution because we would have a negative value for the
second square root

I would say that no solution exist.

8 0

3 years ago

How many solutions does this equation have? -4(5-3x)=12x+20

UNO [17]

Answer: The number of solutions to the given equation is zero.

Step-by-step explanation: We are given to find the number of solutions to the following equation :

$-4(5-3x)=12x+20~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

To find the number of solutions, we must solve the given equation.

The solution of equation (i) is as follows :

$-4(5-3x)=12x+20\\\\\Rightarrow 5-3x=\dfrac{12x+20}{-4}\\\\\Rightarrow 5-3x=-3x-5\\\\\Rightarrow -3x+3x=-5-5\\\\\Rightarrow 0=-10,$ which can never be possible.

So, the given equation has no solution.

Thus, the number of solutions to the given equation is zero.

3 0

4 years ago