Question

Given g(x)=-3x-3g(x)=−3x−3, solve for xx when g(x)=0g(x)=0.

Answer 1

x = - 1

we require to solve - 3x - 3 = 0

add 3 to both sides

- 3x = 3

divide both sides by - 3

x = $\frac{3}{-3}$ = - 1