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3 years ago

A line parallel to the y-axis can be described as vertical. True or False

Mathematics

2 answers:

polet [3.4K]3 years ago

7 0

The answer is true because vertical lines are parallel to each other.
Hope that helped!

IgorC [24]3 years ago

3 0

That is true
hope i helped

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PLEASE NEED THIS DONE AS FAST AS POSSIBLE!!!!!!!!!!!!!!!!!<br> IT MUST BE CORRECT

LuckyWell [14K]

Answer:

1)7.288 feet

2)11.6 feet

3)safe

4) 3.7 feet

5) ∅ $= tan^{-1}(1.5) = 56.31 degrees$

6)∅1 $= tan^{-1}(2) = 63.43 degrees$

∅2 $= tan^{-1}(1.2) = 50.19 degrees$

Step-by-step explanation:

1) The door barn is rectangular in shape. The length is 9 feet and The angle between diagonal and side is 39 degrees.

Applying trigonometry,

tan(39) = $\frac{opposite}{adjacent} = \frac{s}{9}$ = 0.809

Thus, s= $(9)(0.809) = 7.288 feet$

2) Applying pythagoras theorm,

$(Diagonal)^{2} = (9)^{2} + (7.288)^{2} =134.115$

Diagonal length (d) = 11.58 feet. Nearest tenth place = 11.6 feet

3) The length of ladder is 14 foot and height from ground is 13.5 feet.

Applying trigonometry,

sin(∅) = $\frac{opposite}{hypotenous} = \frac{13.5}{14}$ = 0.964

∅ = angle of elevation = $sin^{-1}(0.964)$ = 74.57 ≈ 75 degrees.

Thus tractor can climb safely.

4)Applying, pythgoras theorm,

$14^{2} = (13.5)^{2} + x^{2}$

x = $\sqrt{14^{2}-(13.5)^{2}} = 3.708$

Thus, ladder should be placed at distance 3.7 feet

5)Let angle of elevation be ∅.

tan(∅) = $\frac{30}{20} = 1.5$

∅ $= tan^{-1}(1.5) = 56.31 degrees$

6)After moving 5 feet closer to barn, Let angle of elevation for light near barn be ∅1 and for farther one be ∅2.

Thus,

tan(∅1) = $\frac{30}{15} = 2$

∅1 $= tan^{-1}(2) = 63.43 degrees$

tan(∅2) = $\frac{30}{25} = 1.2$

∅2 $= tan^{-1}(1.2) = 50.19 degrees$

3 0

3 years ago

Plz help number 3d ( can you pls show ur steps of how you got the answer)

denis23 [38]

Answer:

$(\frac{13}{16},-\frac{3}{8})$

Step-by-step explanation:

Midpoint of a segment with the given endpoints $(x_1,y_1)$ and $(x_2,y_2)$ is defined by,

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

In this question endpoints of the segment are,

$Q(-\frac{3}{8},\frac{1}{8})$ and $R(2,-\frac{7}{8})$

Coordinates of the midpoint will be,

$(\frac{-\frac{3}{8}+2}{2},\frac{\frac{1}{8}-\frac{7}{8}}{2})$

= $(\frac{13}{16},-\frac{3}{8})$

Therefore, coordinates of the midpoint are $(\frac{13}{16},-\frac{3}{8})$ .

8 0

3 years ago

Please help

Drupady [299]

Answer:

56°

Step-by-step explanation:

2x+3x+5=90

5x=90-5

5x=85

x=85÷5

x=17

m<2=3x+5=3(17)+5=51+5=56

3 0

4 years ago

MATH ASAP HELP PLEASE!!!

Nezavi [6.7K]

13. 440
14. 15
15. grade 6...not 100% sure on this...might be both grades

8 0

3 years ago

Read 2 more answers

34/14 = x/7 I need help with this its last minute.

Alex_Xolod [135]

Answer:

x = 17

Step-by-step explanation:

Assuming you are solving for x...

34/14 = x/7

The goal is to get x on one side of the equation with nothing else.

The multiplication property of equality states that the equation remains the same if we multiply both sides by the same amount so:

(34/14) * 7 =( x/7) * 7

This simplifies to:

34/2 = x

Which can be simplified even further to:

17 = x

6 0

3 years ago