MATH ASAP HELP PLEASE!!!

What is the distance between 3, 5 and -4, 1

USPshnik [31]

Answer:

Distance = 8.06

Step-by-step explanation:

We have to use the distance formula $d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} }$ .

$(x_{1},y_{1}) =$ coordinates of the first point

$(x_{2},y_{2} ) =$ coordinates of the second point

To solve, plug the appropriate values into the formula.

$d=\sqrt{(-4-3)^{2} +(1-5)^{2} } = \sqrt{65} = 8.062257748$

5 0

3 years ago

C.) 4. Solve the system of equations

raketka [301]

You can set them equal to each other so -3x+4=4x-10 and then you add 3x and 10 on both sides and get7x=14 and then divided both sides by 7 and get x = 2 and check by plugging in and you get -2 for y on both so solution is x=2

7 0

2 years ago

A null hypothesis is being tested. How does the confidence level affect the testing process?

xxTIMURxx [149]

<span>If you have a high confidence level, the chance of rejecting the null hypothesis is rare. If you have a low confidence level, the chance of of rejecting the null hypothesis is nonexistent. If you have a low confidence level, the chance of of rejecting the null hypothesis is rare. If you have a high confidence level, the chance of of rejecting the null hypothesis is high.</span>

5 0

3 years ago

Suppose that in a random sample of 300 employed Americans, there are 57 individuals who say that they would fire their boss if t

otez555 [7]

Answer:

The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 300, \pi = \frac{57}{300} = 0.19$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.19 - 1.96\sqrt{\frac{0.19*0.81}{300}} = 0.1456$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.19 + 1.96\sqrt{\frac{0.19*0.81}{300}} = 0.2344$

The 95% confidence interval for the population proportion is (0.1456, 0.2344). This means that we are 95% sure that the true proportion of employed American who say that they would fire their boss if they could is between 0.1456 and 0.2344.

4 0

3 years ago

A washer and a dryer cost $763 combined. The washer costs $63 more than the dryer. What is the cost of the dryer?

Leni [432]

Answer:

$350

Step-by-step explanation:

w +d = 763

d + 63 = w

-w + d = -63

2d = 700

d = 350

3 0

3 years ago