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3 years ago

MATH ASAP HELP PLEASE!!!

Mathematics

2 answers:

Nezavi [6.7K]3 years ago

8 0

13. 440
14. 15
15. grade 6...not 100% sure on this...might be both grades

Ray Of Light [21]3 years ago

7 0

Each weak it adds by fourty what is 40 × 10

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WILL GIVE BRAINLIEST AND 40 POINTS! NEED THIS ASAP!

e-lub [12.9K]

Answer:

Answer is: B,C

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Components arriving at a distributor are checked for defects by two different inspectors (each component is checked by both insp

miss Akunina [59]

Answer:

The probability that defective component will be detected only by the first inspector is 0.19

The probability that defective component will be detected by exactly one of the two inspectors is 0.38

The probability that all three defective components in a batch escape detection by both inspectors is 0.

Step-by-step explanation:

Part (A)

It is given that The first inspector detects 81% of all defectives that are present, and the second inspector does likewise.

Therefore P(A)=P(B)=81%=0.81

At least one inspector does not detect a defect on 38% of all defective components.

Therefore, $P(\overline{A\cap B})=0.38$

As we know:

$P(\overline{A\cap B})=1-P(A\cap B)=0.38\\P(A\cap B)=1-0.38=0.62$

A defective component will be detected only by the first inspector.

$P(A \cap \bar B)=P(A)-P(A\cap B)\\P(A \cap \bar B)=0.81-0.62\\P(A \cap \bar B)=0.19$

The probability that defective component will be detected only by the first inspector is 0.19

Part (B) A defective component will be detected by exactly one of the two inspectors.

This can be written as: $P(A \cap \bar B)+P(\bar A\cap B)$

As we know:

$P(\bar A \cap B)=P(B)-P(A\cap B)\ and\ P(A \cap \bar B)=P(A)-P(A\cap B)$

Substitute the respective values we get.

$P(A \cap \bar B)+P(\bar A\cap B)=P(A)+P(B)-2P(A\cap B)\\=0.81+0.81-2(0.62)\\=1.62-1.24\\=0.38$

The probability that defective component will be detected by exactly one of the two inspectors is 0.38

Part (C) All three defective components in a batch escape detection by both inspectors

This can be written as: $P(\bar A \cup \bar B)-P(\bar A\cap B)-P(A\cap \bar B)$

As we know $P(\overline{A\cap B})=P(\bar A\cup \bar B)=0.38$

From part (B) $P(\bar A\cap B)+P(A\cap \bar B)=0.38$

This can be written as:

$P(\bar A \cup \bar B)-P(\bar A\cap B)-P(A\cap \bar B)=0.38-0.38=0$

The probability that all three defective components in a batch escape detection by both inspectors is 0

7 0

3 years ago

The earth rotates 360 degrees every day. If I wanted to experience a 90 degree clockwise rotation, where would i need to stand a

Allushta [10]

Conguence is mantained, because reflection preserve distances and angles.

Orientiation is not preserved. You can check this yourself: try to look at a watch through a mirror. You will see it going counterclockwise.

4 0

3 years ago

For breakfast perry adds 1/8 cups of berries to his oatmeal.He has 7/8 cup of berries in his fridge.How many days can he have br

prisoha [69]

Answer:

He has 7 days

Step-by-step explanation:

He consumes 1/8 cups of berries per day, 1/8=1 day

He has 7/8 cups of berries

To get the number of days it takes for 7/8 cups

Number of days=(Number of cups of berries he has)/(The number of berries he consumes in a day)

(7/8)÷(1/8)=(7/8)×8=7 days

4 0

3 years ago

Geometry help please :)

Serhud [2]

The angles of a triangle are right angles

90 = 1/3x + 8

82 = 1/3x

246 = x

Answer is B

4 0

3 years ago