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stellarik [79]
3 years ago
15

Q ÷ 2 -qp ÷ 6; let p = -6 and q = 10

Mathematics
1 answer:
ozzi3 years ago
5 0

Answer:

15

Step-by-step explanation:

1. Plug in the values.

q=10

p=-6

10÷2-(10)(-6)÷6

2. Use PEMDAS.

10÷2+60÷6

5+10

15

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Answer:

0 (zero)

Step-by-step explanation:

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The time period, T, of a simple pendulum is directly proportional to the square root of the length, d, of the pendulum.
bearhunter [10]

Answer: T= 3.54

Step-by-step explanation:

Step 1

Given that

The time period, T, s doirectly proportional  to the square root of the length, d, of the pendulum, we have that

T  ∝  \sqrt{d}

Introducing the constant of proportionality, we have that

T= K\sqrt{d}.

Step 2

When d=6, T=5, K =?

T= K\sqrt{d}.

5 = k\sqrt{6}

5=  k x 2.44949

k =5/2.44949

k =2.041

Therefore, when d = 3 , T= ?

T= K\sqrt{d}

T= 2.041 x \sqrt{3}

T= 3.53511≈ 3.54

4 0
3 years ago
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Answer:

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Step-by-step explanation:

6 0
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