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devlian [24]
3 years ago
9

How do find you equivelant expressions?

Mathematics
1 answer:
Svetlanka [38]3 years ago
4 0
You'll have to start off by finding the variables. Ex:

3(x + 3) - 2(x + 3) 

As you can see here, the two similar variables are x. By using the distributive property, you will get this: 

3x + 9 - 2x + 6 

Next, you'll want to subtract the two variables, since 2x has a - in front of it: 

1x + 9 + 6 

or 

x + 9 + 6 

Then, you want to add the two numbers without the variable: 

x + 15

Your answer is x + 15. 
Hopefully that helped! :) 
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If EF bisects CD, CG=5x-1, GD=7x-13,EF =6x-4 and GF=13, find EG
Anna71 [15]
<span>Segment EG is equal to 19</span>
7 0
4 years ago
You start driving north for 16 miles, turn right, and drive east for another 30 miles. How many miles must you travel to return
wlad13 [49]

Answer:

The distance traveled to return directly to the starting point = 34 miles.

Step-by-step explanation:

Given:

Distance covered in north = 16 miles

Distance covered in east = 30 miles

We have to find the displacement (the shortest distance).

Or

Distance traveled to return directly back to the starting point.

Let the origin be O (0,0) and the distance covered in north be ON and distance covered from right to the east is NE.

Move rightward from N point to the right that is towards east direction.

N is a northern point and E is the eastern point.

ON = 16 miles

NE = 30 miles

We can imagine that it forms a right angled  triangle making 90 (deg) at N by joining E with O (0,0),where OE is the

hypotenuse.

Applying Pythagoras formula.

Where,

Hypotenuse = \sqrt{ON^2+NE^2}

The distance traveled in returning back to the starting point is equivalent to the measure of the hypotenuse.

So,

Hypotenuse        = \sqrt{16^2+30^2}

                            = \sqrt{256+900}

                            = \sqrt{1156}

                            = 34 miles

So the distance traveled to return directly to the starting point = 34 miles.

5 0
3 years ago
Use the discriminant to determine the number of real solutions of the equation.<br> x^2 = -6x - 10
HACTEHA [7]

Answer:

No real solutions.

Step-by-step explanation:

x² + 6x + 10 = 0

a = 1

b = 6

c = 10

D = b² - 4ac = 6² - 4*1*10 = 36 - 40 = - 4

- 4 < 0,

so this equation has no real solutions.

8 0
3 years ago
Read 2 more answers
Can you please help me THAKS! IN A HURRY IT'S midnight and I am trying to finish my work from home My parents allow me to ask
rusak2 [61]

Answer: 6.82

Step-by-step explanation:

So we know the Law of Sines which is that Sin A/a = Sin B/b = Sin C/c. The Sin on top of the fraction is the angle, and the letter on the bottom is the side opposite from that angle.

Our first step is going to be finding the last angle. We have 2 angles already, but one that's missing. We know that all triangles' angles add up to 180, so we can add 68+40=108. Then do 180-108 to get 72. Now we know the third and final angle.

Ok so back to Law of Sines. Now we can plug into that equation. We only need Sin A/a = Sin B/b (It doesn't matter what order you put them in). And remember the lowercase letter at the bottom represents the OPPOSITE side from one of the angles. Since the problem wants the side opposite Sin 68, let's set up a proportion.

\frac{Sin72}{7} =\frac{Sin 68}{x}

Set up we have what we know. We know one side, and opposite that is the angle we already solved for. Now we can cross multiply and end up with:

x (Sin 72)= 7(Sin 68)

Since we want to isolate x, we can divide each side by Sin 72.

x= 7(Sin 68)/Sin 72

So now let's put it into the calculator:

7(Sin 68)=6.2853

Now let's divide 6.2853/Sin 72

And you should be left with 6.82 if you round it!

7 0
4 years ago
Is it possible for two numbers to have a difference of 6, and also a sum of 6?
coldgirl [10]

Answer:

yes

Step-by-step explanation:

sum:

• `x+y=6`

• `y=6-x`

Difference:

• `y-x=6`

• `y=x+6`

4 0
3 years ago
Read 2 more answers
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