Answer:
No, Because students who have the same math grade can be different heights
Step-by-step explanation:
C is the answer DO NOT PICK D
You have the put the correct input and output IN ORDER so D is the wrong answer
Answer:
Step-by-step explanation:
Given
Required
Find r
From the question, we understand that G is a point between D and M:
This implies that:
Substitute values for DM, DG and GM
Collect Like Terms
Solve for r
__________________________
Measurement of "AC" :
(x + 5) + (2x <span>− 11) ;
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Find the measurement of "AB" [which is: "(x+5)" ]:
______________________________________________
First, simplify to find the measurement of "AC" :
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</span>(x + 5) + (2x − 11) ;
= (x + 5) + 1(2x − 11) ;
= x + 5 + 2x − 11 ;
→ Combine the "like terms" ;
x + 2x = 3x ;
5 − 11 = - 6 ;
______________
to get: 3x − 6 ;
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So, (x + 5) + (2x − 11) = 3x − 6 ;
_______________________________
Solve for: "(x + 5)"
_______________________________
We have:
_______________________________
(x + 5) + (2x − 11) = 3x − 6 ;
Subtract: "(2x − 11)" ; from EACH SIDE of the equation ;
to isolate "(x + 5)" on one side of the equation;
and to solve for "(x + 5)" ;
________________________________________________________
→ (x + 5) + (2x − 11) − (2x − 11) = (3x − 6) − (2x − 11) ;
→ (x + 5) = (3x − 6) − (2x − 11) ;
_________________________________________________
Note: Simplify: "(3x − 6) − (2x − 11)" ;
→ (3x − 6) − (2x − 11) ;
= (3x − 6) − 1(2x − 11) ;
= 3x − 6 − 2x + 11 ;
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→ Combine the "like terms" :
_____________________________
+3x − 2x = 1x = x ;
-6 + 11 = 5 ;
_____________________________
To get: x + 5 ;
So we have:
______________________________
x + 5 = x + 5 ;
______________________________
So, x = all real numbers.
x = <span>ℝ </span>
Answer:
See the three attached images.
Step-by-step explanation:
image1 shows the intersection of b and c: 
. (green "football")
image2 shows the <u>complement</u> of a (outside a): 
(yellow)
image3 shows the intersection of those sets: 
(green "football with a bite out of it") :-)
