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3 years ago

9

A circle is divided into 8 sectors. Each sector has an area of approximately 5 square inches. What is the approximate area of th

e circle?
Question 5 options:

A. 25 square inches

B. 40 square inches

C. 15.7 square inches

D. 78.5 square inches

1 answer:

vovikov84 [41]3 years ago

8 0

Answer: 8×5 =40
B. 40 square inches

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Peppermint candies per jar

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Leaf #2 because 27 and 23 are closest to 30

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Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

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2 years ago

Talulah is an ecologist who studies the change in the penguin population of Antarctica over time. She observed that the populati

Oksana_A [137]

Answer:

P(t) = 27000 * (1/9)^(t/4)

Step-by-step explanation:

This problem can me modelled with an exponencial formula:

P = Po * (1+r)^t

Where P is the final value, Po is the inicial value, r is the rate and t is the amount of time.

In this problem, we have that the inicial population/value is 27000, the rate is -8/9 (negative because the population decays), and the time t is in months, so as the rate is for every 4 months, we use the value (t/4) in the exponencial.

So, our function will be:

P(t) = 27000 * (1-8/9)^(t/4)

P(t) = 27000 * (1/9)^(t/4)

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3 years ago

Read 2 more answers

Another question to stimulate the mind 11248 what's the 11th digit and why

choli [55]

Answer:

First member-> 1 -> "1 one"

Second member-> 11 -> "2 ones"

Third member-> 21 -> "1 two, 1 one"

Fourth member -> 1211 -> "1ones, 1 two, 2 ones"

Fifth member-> 111221 -> "3 ones, 2 twos, 1 ones"

Sixth member-> 312211 -> "1three, 1 one, 2 twos, 2 ones"

Seventh member-> 13112221 ->" 1 one, 1 three, 2 ones, 3 twos, 1 one"

Step-by-step explanation:

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2 years ago

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the answer is on the photo

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2 years ago