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3 years ago

What is x-2y=-1 and 2x+y=4 using elimination step by step

Mathematics

1 answer:

otez555 [7]3 years ago

5 0

Answer:

x = 7/5 , y = 6/5

Step-by-step explanation using elimination:

Solve the following system:

{x - 2 y = -1 | (equation 1)

2 x + y = 4 | (equation 2)

Swap equation 1 with equation 2:

{2 x + y = 4 | (equation 1)

x - 2 y = -1 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y = 4 | (equation 1)

0 x - (5 y)/2 = -3 | (equation 2)

Multiply equation 2 by -2:

{2 x + y = 4 | (equation 1)

0 x+5 y = 6 | (equation 2)

Divide equation 2 by 5:

{2 x + y = 4 | (equation 1)

0 x+y = 6/5 | (equation 2)

Subtract equation 2 from equation 1:

{2 x+0 y = 14/5 | (equation 1)

0 x+y = 6/5 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 7/5 | (equation 1)

0 x+y = 6/5 | (equation 2)

Collect results:

Answer: {x = 7/5 , y = 6/5

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Before a sale, an item’s price was $38.00; during the sale, it was 15% off. What was the sale price?

Pani-rosa [81]

38 times (1-15%)
$32.3

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3 years ago

6 children and 2 adults are going to the circus. Children tickets are on sale,half price of adult tickets totaling $54. How much

Anon25 [30]

Answer:

Price of 1 adult ticket is $10.8 and Price of 1 children ticket is $5.4.

Step-by-step explanation:

Given:

Number of adults = 2

Number of Children = 6

Total Amount of tickets sold = $54.

We need to find the price of one children's ticket and one adult ticket.

Solution:

Let the Cost of 1 adult ticket be 'x'.

Now Given:

Children tickets are on sale,half price of adult tickets.

Cost of 1 Children ticket = $\frac{1}{2}x$

Total Amount is equal to Number of adults multiplied by Cost of adult ticket plus Number of Children multiplied by Cost of Children ticket.

Framing in equation for we get;

$2x+\frac{1}{2}x\times 6=54\\\\2x+3x=54\\\\5x=54\\\\x=\frac{54}{5} = \$10.8$

Cost of 1 adult ticket = $10.8

Cost of 1 children ticket = $\frac{x}{2}=\frac{10.8}{2} = \$5.4$

Hence Price of 1 adult ticket is $10.8 and Price of 1 children ticket is $5.4.

7 0

3 years ago

What is the product of the 2 solutions of the equation x^2+3x-21=0

Advocard [28]

X²+3x-21=0

1) we solve this square equation:
x=[-3⁺₋√(9+84)] / 2=(-3⁺₋√93)/2
We have two solutions:
x₁=(-3-√93)/2
x₂=(-3+√93)/2

2) we compute the product of the 2 solutions found.
[(-3-√93)/2][(-3+√93)/2] =(-3-√93)(-3+√93) / 4=
=(9-93)/4=-84/4=-21

Answer: the product of the 2 solutions of this equation is -21

3 0

3 years ago

1.find the sum. (3^3+5x^2+3x-7)+(8x-6x^2+6) 2. Find the Difference: (8x-4x^2+3\)-(x^3+7x^2+3x-8)

vlada-n [284]

$(3^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=27\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=-x^2+11x+26$

or if you mean (3x^3+5x^2+3x-7)+(8x-6x^2+6):

$(3x^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=3x^3\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=3x^3-x^2+11x-1$

$(8x-4x^2+3)-(x^3+7x^2+3x-8)=\\\\=\underline{8x}\ \underline{\underline{-\ 4x^2}}+3-x^3\ \underline{\underline{-\,7x^2}}\ \underline{-\,3x}+8=\\\\=-x^3-11x^2+5x+10$

3 0

2 years ago

Find the volume of a rectangular prism with a base that has an area of 22 square centimeter and a height of 8 centimeters.

Jlenok [28]

Answer:

176cm³

Step-by-step explanation:

Multiply area of base times height

22cm² × 8cm = 176cm³

3 0

3 years ago