Ask question

Ask question

All categories

3 years ago

5

Classify each of the following as an observation, a law, or a theory. (a) All matter is made of tiny, indestructible particles c

alled atoms. (b) When iron rusts in a closed container, the mass of the container and its contents does not change. (c) In chemical reactions, matter is neither created nor destroyed. (d) When a match burns, heat is evolved.

1 answer:

jenyasd209 [6]3 years ago

5 0

Answer: a) Theory

Explanation: “Dalton’s Atomic Theory”

b) When iron rusts in a container... is an Observation

c) The “Law”of Conservation of Mass

d) is an observation

You might be interested in

Two blocks are connected by a massless rope that passes over a 1 kg pulley with a radius of 12 cm. The rope moves over the pulle

tangare [24]

Answer:

$F=1.159$

Explanation:

From the question we are told that:

Mass of pulley $M=1kg$

Radius $r=12cm$

Mass of block A $M_a=2.1kg$

Mass of block B $m_b=4.1kg$

Spring constant $\mu= 358 J/m2$

Generally the equation for Torque is mathematically given by

Since $\sumF=ma$

At mass A

$T_2-f_3=2.1a$

At mass B

$4.8-T_1=4.1a$

At Pulley

$R(T_1-T_2)=\frac{1*1*R^2}{2}\frac{a}{R}$

$R(T_1-T_2)=0.55a$

Therefore the equation for total force F

At mass A+At mass B+At Pulley

$(T_2-f_3+4.8-T_1+R(T_1-T_2)=2.1a+4.1a+0.55a$

$(T_2-f_3+4.8-T_1+R(T_1-T_2)=2.7a+4.8a+0.55a$

$-f_3+4.1=6.75a$

$-f_3=6.75a+4.8$

Since From above equation

$M_{eff}=6.7kg$

Therefore

$T=2\pi \sqrt{{\frac{M_{eff}}{k}}$

$T=2\pi \sqrt{{\frac{6.75}{\mu}}$

$T=0.862s$

Generally the equation for frequency is mathematically given by

$F=\frac{1}{T} \\F=\frac{1}{0.862}$

$F=1.159$

3 0

3 years ago

a swimmer can develop a maximum speed of 8m/s when he is swimming in a pool. calculate the time that is required to pass the dis

8090 [49]

Answer:

2

Explanation:

6 0

3 years ago

I need help with this for physics

Vanyuwa [196]

Answer:

V=Volts

I= Amperes

R= Ohms

8 0

3 years ago

An electron initially has a speed 16 km/s along the x-direction and enters an electric field of strength 27 mV/m that points in

weqwewe [10]

Answer:

a) $t=1.4\times 10^{-5}\ s$

b)S= 46.4 cm

Explanation:

Given that

Velocity = 16 Km/s

V= 16,000 m/s

E= 27 mV/m

E=0.027 V/m

d= 22.5 cm

d= 0.225 m

a)

lets time taken by electron is t

d = V x t

0.225 = 16,000 t

$t=1.4\times 10^{-5}\ s$

b)

We know that

F = m a = E q ------------1

Mass of electron ,m

$m=9.1\times 10^{-31}\ kg$

Charge on electron

$q=1.6\times 10^{-19}\ C$

So now by putting the values in equation 1

$a=\dfrac{E q}{m}$

$a=\dfrac{1.6\times 10^{-19}\times 0.027}{9.1\times 10^{-31}}\ m/s^2$

$a=4.74\times 10^{9}\ m/s^2$

$S= ut+\dfrac{1}{2}at^2$

Here initial velocity u= 0 m/s

$S= \dfrac{1}{2}\times 4.74\times 10^{9}\times (1.4\times 10^{-5})^2\ m$

S=0.464 m

S= 46.4 cm

S is the deflection of electron.

4 0

4 years ago

Read 2 more answers

Would a 500 μF or 100 μF capacitor keep a light bulb on longer? Explain your reasoning

balandron [24]

Answer:

The 500 would be able to keep a light bulb on longer.

Explanation:

The 500 would be able to hold more charge than the 100 which means it can keep the light bulb lit for longer.

5 0

3 years ago