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2 years ago

Which of the following is an advantage of asexual reproduction compared to sexual reproduction?

Physics

2 answers:

Alina [70]2 years ago

8 0

Answer:

rapid mode of multiplication

Explanation:

in asexual reproduction they reproduce faster

azamat2 years ago

6 0

Answer:

Asexual reproduction requires less energy and will produce more offspring over time

Explanation:

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What is the mass of a truck in grams of it produces a force of 1500N while accelerating at a rate of 6 m/s²?

aleksley [76]

Answer:

250,000

Explanation:

<h2>formula = ( F=ma </h2>

F=1500N
a=6m/s^2
F= ma
m=?
1500/6 = m
m=250 kg
1kg =1000gm so 250kg =250,000gm
m =250×10^3 gm

5 0

2 years ago

A bicyclist is travelling at 25 m/s when he begins to decelerate at -4m/s2 . How fast is travelling after 5 seconds

Umnica [9.8K]

Initial velocity (Vi) = 25 m/s

acceleration (a) = $-4 m/s^{2}$

time interval (t) = 5 sec

let us assume that final velocity after 5 sec be Vf

As acceleration is constant, we can apply the the equation of motion with constant acceleration i.e. $V_{f} = V_{i} + at$

Hence, $V_{f} = 25 +(-4)(5) = 25 -20 = 5 m/s$

so, the velocity of bicyclist will be 5 m/s after 5 sec

7 0

2 years ago

An air conditioner running with R-134a on a cycle executed under the saturationdome between the pressure limits of 0.8 MPa and 0

ohaa [14]

Answer:

The COP of the system is = 4.6

Explanation:

Given data

Higher pressure = 1.8 M pa

Lower pressure = 0.12 M pa

Now we have to find out high & ow temperatures at these pressure limits.

Higher temperature corresponding to pressure 1.8 M pa

$T_{H} = 62.9$ °c = 335.9 K

Lower temperature corresponding to pressure 0.2 M pa

$T_{L} = - 10.1$ °c = 262.9 K

COP of the system is given by

$COP = \frac{T_{L} }{T_{H} -T_{L} }$

$COP = \frac{335.9}{335.9 -262.9}$

COP = 4.6

Therefore the COP of the system is = 4.6

8 0

2 years ago

The total units by an objects as it changes position is called _____ ?

Alika [10]

Change in position of object = Displacment

7 0

2 years ago

0/2 File Limit

slamgirl [31]

Answer:

Speed at which it will reach the ground is given as

$v_f = 46.8 m/s$

Total time for which it will remain in air is given as

t = 6.3 s

Explanation:

As we know that the object is projected upwards with speed

$v_i = 15 m/s$

$g = - 9.81 m/s^2$

now when it will reach the ground then we have

$y = v_y t + \frac{1}{2} at^2$

so we have

$-100 = 15 t - \frac{1}{2}(-9.81) t^2$

$4.905 t^2 - 15 t - 100 = 0$

so we have

$t = 6.3 s$

Now speed of the object when it reaches the ground is given as

$v_f = v_i + at$

$v_f = -15 + (9.81)(6.3)$

$v_f = 46.8 m/s$

8 0

2 years ago