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sashaice [31]
3 years ago
9

Explain Well please.

Mathematics
1 answer:
Art [367]3 years ago
7 0
The answer is C,
as she uses SSS to prove its congruent, she uses sides instead of angles so option a and d is not correct. as it needs to prove triangle pqr is congruent to triangle sqr, its not necessary to prove PQ is equal to QR. so the answer is c
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High concentrations of carbon monoxide CO can cause coma and possible death. The time required for a person to reach a COHb leve
ale4655 [162]

Answer:

A) 10.38hours

B) 617.95 is the concerntration of CO

Step-by-step explanation:

A) when x=600

T= 0.0002x^2 - 0.316x + 127.9

T= 0.0002(600)^2 -0.316(600) + 127.9

T= 10.38secs

B) to find the concerntration, use Almighty formular

X=-b+-sqrt(b^2-4ac)/2a

0.0002x^2-0.316x-127.9=9

0.0002x^2 - 0.316x + 118.9=0

X= 0.316 +- sqrt(0.316^2) -4(0.0002×118.9)/(2×0.0002)

X= 0.316+(0.68817/0.0004)=962.05 or

X=-0.316 -0.68817/0.0004 =617.95

Therefore X is within the domain of 617.95 is the concerntration

5 0
3 years ago
A circle has the equation x^2+y^2+x-6y+9=0. Find the center and any x or y intercepts.
Softa [21]
We know:x^2+y^2+x−6y+9=0So, we complete the square as such:x^2+y^2+x−6y+9=x^2+x+y^2−6y+9=(x+1/2)^2+(y−3)^2=(1/2)^2=1/4
5 0
3 years ago
A rocket is launched from ground level. The height of the rocket can be
abruzzese [7]

Answer: 11.25 secs

Step-by-step explanation:

So in this sense the rockets origin or the ground is modeled at h=0 so the time required if used on a table shows that h=0 between the values of 11 and 12. So if you plug and chug decimal values between these two values you get exactly 0 at t=11.25 so it takes approximately 11.25 seconds for the rocket to return to the ground

3 0
2 years ago
3(12+b)=3x12+3xb
Vikentia [17]
This is the distributive property. You take what is outside of the parenthesis and DISTRIBUTE it inside the parenthesis.
4 0
3 years ago
Q13 A gardener needs to buy compost to fill this tub.
REY [17]

Answer:

  5 bags

Step-by-step explanation:

The volume of the tub is the product of its dimensions:

  V = (1.8 m)(0.5 m)(0.25 m) = 0.225 m³

There are 1000 L in 1 m³, so this volume in liters is ...

  (0.225 m³)(1000 L/m³) = 225 L

At 50 L per bag, the gardener needs ...

  (225 L)/(50 L/bag) = 4.5 bags

The gardener probably cannot purchase a partial bag, so must buy more than is needed.

The gardener must buy 5 bags of compost to fill the tub.

8 0
2 years ago
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