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Xelga [282]
3 years ago
6

What is 2/3+1/4 please answer immediately

Mathematics
2 answers:
Bond [772]3 years ago
6 0

Answer:11/12

Step-by-step explanation:

Korvikt [17]3 years ago
3 0

Answer:

11/12

Step-by-step explanation:

hi the answer is in the pic

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What is one of the solutions to the following system of equations? y2 x2 = 53 y − x = 5 (−10, −5) (−7, −2) (7, 2) (5, 10).
Aliun [14]

The solution of the system of equation is (-7, -2).

<h2>Given</h2>

The system of the equations;

\rm y^2 + x^2 = 53 \\\\y -x = 5

From equation 1

\rm  y -x=5\\\\y = 5+x

Substitute the value of y in equation 1

\rm y^2+x^2=53\\\\(5+x)^2+x^2=53\\\\25+x^2+10x+x^2=53\\\\2x^2+10x+25-53=0\\\\2 x^2 + 10x - 28 = 0     \\\\Divide \ by \ 2 \ both \ side \ the \ equation\\\\x^2 + 5x - 14 = 0\\\\x^2-7x+2x-14=0\\\\x(x-7) + 2(x-7) =0\\\\(x-7) \ (x+2)=0\\\\x-7=0 \ \ x = 7\\\\x +2 =0 \ \ x=-2

The value of x= 2 is rejected because x = 2 not satisfy the equation.

Substitute 2 for the value of x in equation II

y − x = 5

y – 2 = 5

y = 5 +2

y = 7 (x =2, y =7) … Not included in the options

If x = -7

Substitute the value of x = -7 in the equation

\rm y -x=5\\\\y - (-7)=5\\\\y +7= 5\\\\y = 5-7\\\\y = -2

Hence, the solution of the system of equation is (-7, -2).

To know more about System of Equation click the link given below.

brainly.com/question/1495351

6 0
2 years ago
1.<br> Find the least common multiple.<br> 20 and 12
musickatia [10]

Answer:

answer 60

Step-by-step explanation:

The LCM(12, 20) = 60.

4 0
3 years ago
PLZ HELP ME WITH THIS ONE ALSO :)
Norma-Jean [14]

Answer:

9 \times  \sqrt{3 }

Step-by-step explanation:

x =  \cos(30)  \times 18 \\ x = 9 \sqrt{3}

5 0
3 years ago
Use the equation below to find y, if m=6, x=3, and b = 10.<br> y=mx+b
ICE Princess25 [194]

Answer:

y = 28

Step-by-step explanation:

y = mx + b

plug in values

y = (6)(3) + (10)

multiply

y = 18 + (10)

add

y = 28

8 0
3 years ago
Read 2 more answers
How many 0 are in one million
Shalnov [3]

Answer:

6

Step-by-step explanation:

4 0
3 years ago
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