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Bezzdna [24]
2 years ago
6

Which graph represents the function f (x) = StartFraction 3 x minus 2 Over x minus 2 EndFraction?

Mathematics
1 answer:
Gelneren [198K]2 years ago
4 0

Step-by-step explanation:

answer is in photo above

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The line x+ 2y = 9 intersects the curve xy + 18 = 0 at the points A and B. Find the coordinates of A and B.
victus00 [196]
Subtracting the second equation by 18 on both sides, we have xy=-18. Next, we divide both sides by x to get y=-18/x  Plugging that into the first equation, we have x+2(-18/x)=9. Multiplying both sides by x, we get x^2-36=9x. After that, we subtract both sides by 9x to get x^2-9x-36=0. Finding 2 numbers that add up to -9 but multiply to -36, we do a bit of guess and check to find the answers to be -12 and 3. Factoring it, we get 
x^2-12x+3x-36=x(x-12)+3(x-12)=(x+3)(x-12). To find the x values, we have to find out when 0=(x+3)(x-12). This is simple as when you multiply 0 with anything, it is 0. Therefore, x=-3 and 12. Plugging those into x=-18/y, we get x=-18/y and by multiplying y to both sides, we get xy=-18 and then  we can divide both sides by x to get -18/x=y. Plugging -3 in, we get -18/-3=6 and by plugging 12 in we get -18/12=-1.5. Therefore, our points are (-3,6) and (12, -1.5)
6 0
3 years ago
Can someone help! I know the answer I just need step by step!
baherus [9]

Answer:

4 \sqrt{2}

Step-by-step explanation:

Rewrite 32 as the product of 16 and 2:

\implies \sqrt{32}=\sqrt{16 \cdot 2

Apply exponent rule \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}

\implies \sqrt{16 \cdot 2}=\sqrt{16}\sqrt{2}

Rewrite 16 as 4²:

\implies \sqrt{16}\sqrt{2}=\sqrt{4^2}\sqrt{2}

Apply exponent rule \sqrt{a^2}=a

\implies \sqrt{4^2}\sqrt{2}=4 \sqrt{2}

6 0
2 years ago
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