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Sindrei [870]
3 years ago
15

The volume of a cube is 125m3 if I L of a paint covers 6m2, how many liters of paint are needed to paint the outside of the cube

Mathematics
1 answer:
Effectus [21]3 years ago
6 0

Answer:

36 liters

Step-by-step explanation:

step 1

Find the length side of the cube

we know that

The volume of the cube is given by

V=b^3

we have

V=125\ m^3

substitute

125=b^3

solve for b

b=5\ m

step 2

Find the surface area of the cube

The surface area of a cube is equal to

SA=6b^2

substitute the value of b

SA=6(6)^2=216\ m^2

step 3

Find out how many liters of paint are needed to paint the outside of the cube

we know that

1 L of a paint covers 6m2

so using proportion

\frac{1}{6}\ \frac{L}{m^2} =\frac{x}{216}\ \frac{L}{m^2} \\\\x=216/6\\\\x=36\ L

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A rectangular park had a perimeter of 18 miles. It is 7 miles wide. What is the area of the park?
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7 0
3 years ago
What number should be added to both sides of the equation to complete the square ? x2 + 12x = 11
Korvikt [17]
You can add a lot of numbers (or so I think). One number I think you can add is 31. 
3 0
3 years ago
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Simplify. -10m+2m^4-13m-20m^4
Ulleksa [173]
First one:

you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so

when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)

-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m


add
-10m-13m+2m^4-20m^4
-23m-18m^4




second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms

(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
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8 0
3 years ago
5×=15+10y,3×+7y=31 it's for tomorrow pls​
Katarina [22]

Answer:

x = 6.39, y = 1.69 is the solution of the given equation system.

Step-by-step explanation:

Here, the given set of equation is:

5 x = 15 + 10 y  ⇒ 5 x - 10 y = 15   ...... (1)

3 x +7 y = 31   ............. (2)

Now, the coefficient of x in first equation id 5 and in second  is 3.

So, MULTIPLY (1) with 3 and (2) with -5 , we get:

15 x - 30 y = 45

-15 x- 35 y = -155

<u>ADD BOTH EQUATIONS ,</u> we get:

15 x - 30 y  -15 x- 35 y = 45 - 155

or, -65 y  = -110

or, y = 110/65 = 1.69

Put y  = 1.69 in 3 x +7 y = 31 , we get:

3(x) +  7 (1.69) =31

⇒ 3 x = 19.17 or x = 6.39

Hence, x = 6.39, y = 1.69 is the solution of the given equation system

3 0
3 years ago
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