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3 years ago

What do 110°, 250°, and -470° angles have in common?

Mathematics

2 answers:

gladu [14]3 years ago

5 0

They are all obtuse angles

Nadusha1986 [10]3 years ago

4 0

They are all larger than 90 degrees, and in a triangle they would all be obtuse angles.

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real estate julie bought a house for $100,00 five years ago. if the value of the house has appreciated 5% per year , how much is

Stels [109]

To find the answer, turn the appreciated percent into a decimal:

5% ----> .05 (Divide by 100)

Then multiply it by the total value:

100,000 x .05 = 5000

Then add that to the total:

105,000

So the house is worth a total of $105,000.

Hope this helps!

5 0

4 years ago

Please help me Simplify: 6! − 3!

djverab [1.8K]

Answer: Option B 3!((6×5×4)-1)

Step-by-step explanation:

6! - 3!

= (1×2×3×4×5×6) - (1×2×3)

= 720 - 6

= 714

As you told you forgot to put options lemme answer it.

It will be option B

3!((6×5×4)-1)

It will be 6((6×5×4)-1)

= 6(120) -6

= 720 - 6

= 714

please click thanks and mark brainliest if you like :)

5 0

3 years ago

Read 2 more answers

The perimeter of a regulation singles tennis court is 210 feet and the length is 57 feet less than five times the width.

Marianna [84]

Answer:

Length = 24 and Width = 81

Step-by-step explanation:

Let Width be W

then Length = W-57

Perimeter of rectangle = 2(Length + Width)

=2 (W-57+W)= 210

4W- 114= 210

4W= 324

W= 81

Then Length = 81-57 = 24

4 0

3 years ago

What is the least common multiple of 16, 20, and 50

IRINA_888 [86]

Answer:

400

Step-by-step explanation:

The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly.

3 0

4 years ago

Read 2 more answers

A researcher wishes to estimate the average blood alcohol concentration (BAC) for drivers involved in fatal accidents who are f

Mnenie [13.5K]

Answer:

A 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

Step-by-step explanation:

We are given that a researcher randomly selects records from 60 such drivers in 2009 and determines the sample mean BAC to be 0.16 g/dL with a standard deviation of 0.080 g/dL.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean BAC = 0.16 g/dL

s = sample standard deviation = 0.080 g/dL

n = sample of drivers = 60

$\mu$ = population mean BAC in fatal crashes

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 90% confidence interval for the population mean, $\mu$ is;

P(-1.672 < $t_5_9$ < 1.672) = 0.90 {As the critical value of t at 59 degrees of

freedom are -1.672 & 1.672 with P = 5%} P(-1.672 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.672) = 0.90

P( $-1.672 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $0.16-1.672 \times {\frac{0.08}{\sqrt{60} } }$ , $0.16+1.672 \times {\frac{0.08}{\sqrt{60} } }$ ]

= [0.143, 0.177]

Therefore, a 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

7 0

3 years ago