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Vera_Pavlovna [14]
3 years ago
10

What do 110°, 250°, and -470° angles have in common?

Mathematics
2 answers:
gladu [14]3 years ago
5 0
They are all obtuse angles
Nadusha1986 [10]3 years ago
4 0
They are all larger than 90 degrees, and in a triangle they would all be obtuse angles.
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Joe has 37 coins consisting of nickels, dimes, and quarters. There are four more nickels than dimes and two more quarters than n
astraxan [27]

Answer:

  15

Step-by-step explanation:

Let n, d, q represent the numbers of nickels, dimes, and quarters. The problem statement tells us ...

  n +d +q = 37

  n = d +4

  q = n +2

___

Rearranging the second equation gives ...

  d = n -4

Substituting that into the first, we get ...

  n + (n -4) +q = 37

  2n +q = 41 . . . . . . . add 4 and simplify

Rearranging the third original equation gives ...

  n = q -2

Substituting into the equation we just made, we get ...

  2(q -2) +q = 41

  3q = 45 . . . . . . . . add 4 and simplify

  q = 15 . . . . . . . . . divide by 3

Joe has 15 quarters.

_____

<em>Check</em>

The number of nickels is 2 fewer, so is 13. The number of dimes is 4 fewer than that, so is 9. The total number of coins is 15 + 13 + 9 = 37, as required.

5 0
3 years ago
What is the function of y=-3|x+5|+7
zheka24 [161]

Answer:   Graph coordinates down below

Step-by-step explanation: Please mark brainliest of you feel this helped

1 2

3 12

10 110

5 0
3 years ago
A particular airport has beacons on the ground 5 km out from the start of each runway. An airplane is directly over this beacon
AleksAgata [21]

Answer:

The direct distance from the plane to the start of the runway is approximately 5.0623 km

Step-by-step explanation:

The locations of the beacons on the runway, x = 5 km from the start of each runway

The angle of elevation of the airplane from the runway, θ = 9°

Let 'R' represent the direct distance from the plane to the start of the runway

The horizontal distance from the start of the runway to the beacon, 'x', the distance from the plane to the start of the runway, 'R', and the vertical height of the plane, 'h' form a right triangle with rides x, R, and h

By trigonometric ratios, we have;

cos\angle \theta = \dfrac{The \ length \ of \ the \ adjacent\ leg  \ to \ \angle \theta}{The \ length \ of \ the \ hypotenuse \ side} = \dfrac{x}{R}

Therefore, we have;

cos (9 ^{\circ}) = \dfrac{x}{R} = \dfrac{5}{R}

From which we have;

R=  \dfrac{5}{cos (9 ^{\circ}) } \approx 5.0623

The direct distance from the plane to the start of the runway, R ≈ 5.0623 km

7 0
3 years ago
1 + 1 =<br> long method pls
MAVERICK [17]
When 1 is added to another 1 they join together to form a 2. Bruh idk what 1+1 long method is. But I hope it helped.
5 0
3 years ago
The company wants to print 8000 newspapers daily. How many magazines at most can the company print daily with the remaining numb
taurus [48]

Answer:

Option A.  

The company can print 800 magazines at most

Step-by-step explanation:

Let

N------> the number of newspapers

M------> the number of magazines

we know that

0.5N+2.5M\leq 6,000

For N=8,000

Substitute the value of N in the inequality and solve for M

so

0.5(8,000)+2.5M\leq 6,000

4,000+2.5M\leq 6,000

2.5M\leq 6,000-4,000

2.5M\leq 2,000

M\leq 800\ magazines

4 0
3 years ago
Read 2 more answers
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