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Vera_Pavlovna [14]
3 years ago
10

What do 110°, 250°, and -470° angles have in common?

Mathematics
2 answers:
gladu [14]3 years ago
5 0
They are all obtuse angles
Nadusha1986 [10]3 years ago
4 0
They are all larger than 90 degrees, and in a triangle they would all be obtuse angles.
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(50 POINTS! PLEASE HELP!) Alang has a bag that contains pineapple chews, strawberry chews, and lime chews.
Lelechka [254]

Answer:

<u>1/13</u>

Step-by-step explanation:

Probability (lime chew) :

  • No. of times lime chew was selected / Number of times experiment was conducted
  • 2/26
  • <u>1/13</u>
8 0
2 years ago
Read 2 more answers
Help me! What is the answer to this question!? Provide a step by step explanation please.
zmey [24]

Answer:

x = -5 or x= 2

Step-by-step explanation:

|-4x-6| = 14

There are two solutions, one positive and one negative

-4x-6 = 14       -4x-6 = -14

Add 6 to each side

-4x-6+6 = 14+6       -4x-6+6 = -14+6

-4x = 20                      -4x = -8

Divide by -4

-4x/-4 = 20/-4               -4x/-4 = -8/-4

x = -5                                x = 2

3 0
3 years ago
Read 2 more answers
Step by step please and thank you.
cupoosta [38]

Answer:

  the probability is 2/9

Step-by-step explanation:

Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).

  p(dime first) = 4/10 = 2/5

Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.

The joint probability of these two events occurring sequentially is the product of their probabilities:

  p(dime then nickel) = (2/5)×(5/9) = 2/9

_____

<em>Alternate solution</em>

You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.

  p(dime/nickel) = 20/90 = 2/9

8 0
2 years ago
Estimate each quotient 195 divided by 4
sweet-ann [11.9K]
....................48.5 I think
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2 years ago
How can I learn to do standard notation and scientific notation?
jonny [76]
Just watch videos on youtube.
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3 years ago
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