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AnnZ [28]
3 years ago
9

Power legitimated by long-standing custom is

Geography
1 answer:
sukhopar [10]3 years ago
7 0
Traditional authority

Hope this helps! ^_^
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You have two samples of ocean crust that are the same age and have the same magnetite orientation. In sample A, the width of the
slega [8]

Answer:

It is evident from the distinct magnetite orientation that these two rocks came from the mid ocean ridges.

If the rocks were obtained at the same time, sample A which is the rock with wider band of distinct magnetite orientation (2m) must be from the Easy Pacific Rise and the rock sample B with the shorter band of distinct magnetite orientation (1m) is from the Mid-Atlantic Ridge.

Explanation:

The Mid-Atlantic Ridge is a slow spreading center (leading to broader bands of magnetite orientation). It spreads 2-5 centimeters (0.8-2 inches) every year and forms an ocean trench about the size of the Grand Canyon.

The East Pacific Rise, on the other hand, is a fast spreading center (wide band of distinct magnetite orientation). It spreads about 6-16 centimeters (3-6 inches) every year. There is not an ocean trench at the East Pacific Rise, because the seafloor spreading is too rapid for one to develop!

Hope this helps!!!

7 0
4 years ago
Wind farms are a source of renewable energy found around the world
pantera1 [17]

Wind farms are a source of renewable energy found around the world. One of the world's fastest-growing energy sources is wind energy since it has numerous economic benefit.

A renewable and clean energy source is wind power. Utilizing mechanical energy to spin a generator and generate electricity, wind turbines capture wind energy.

In addition to being a plentiful and limitless resource, wind also generates power without consuming any fuel or damaging the environment. The main renewable energy source in the United States is still wind, which aids in lowering our dependency on fossil fuels.

Annually, wind energy helps save 329 million metric tons of carbon dioxide emissions, which is the same amount of emissions produced by 71 million automobiles and contributes to acid rain, pollution, and greenhouse gas emissions.

Learn more about Renewable Energy here:

brainly.com/question/79953

#SPJ4

5 0
2 years ago
.-Indica a qué fuente o forma de energía se refieren estas afirmaciones.-
Alborosie
Check on Socratic it might help 1234 45567 free
3 0
3 years ago
Why does eastern Norway have colder and snowier winters than western Norway?
katrin [286]
Mountains reduce the eastern flow of milder air.
4 0
4 years ago
. If the fastest passenger aircraft can fly 0.45 km/s (1000 mph), how long would it take to reach the sun? The galactic center?
nadezda [96]

Answer:

The passenger aircraft would take 10.542 years to reach the Sun from the Earth.

The passenger aircraft would take 1.733\times 10^{10} years to reach the gallactic center.

Explanation:

The distance to the sun from the Earth is approximately equal to 1.496\times 10^{8}\,km, if the passenger travels at constant speed, then the time needed to reach the sun is calculated by the following kinematic formula:

\Delta t = \frac{s}{v} (1)

Where:

s - Travelled distance, measured in kilometers.

v - Speed of the passenger aircraft, measured in kilometers per second.

\Delta t - Travelling time, measured in seconds.

If we know that s = 1.496\times 10^{8}\,km and v = 0.45\,\frac{km}{s}, then the travelling time is:

\Delta t = \frac{1.496\times 10^{8}\,km}{0.45\,\frac{km}{h} }

\Delta t = 3.324\times 10^{8}\,s

\Delta t = 3847.736\,days

\Delta t = 10.542\,years

The passenger aircraft would take 10.542 years to reach the Sun from the Earth.

The distance between the Earth and the galactic center is approximately equal to 2.460\times 10^{17}\,km. If the passenger travels at constant speed and if we know that s = 2.460\times 10^{17}\,km and v = 0.45\,\frac{km}{s} , then the travelling time is:

\Delta t = \frac{2.460\times 10^{17}\,km}{0.45\,\frac{km}{s} }

\Delta t = 5.467\times 10^{17}\,s

\Delta t = 6.327\times 10^{12}\,days

\Delta t = 1.733\times 10^{10}\,years

The passenger aircraft would take 1.733\times 10^{10} years to reach the gallactic center.

3 0
3 years ago
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