How to I get 25ft to centimeters?

Compare the quantities in Column A and Column B.

GaryK [48]

The y-intercept of $2y = 3x - 4$ and the y-intercept of $4x - 2y=4$ are equal

The equations are given as:

$2y = 3x - 4$

$4x - 2y=4$

Make y the subject in both equations

<u>First equation</u>

$2y = 3x - 4$

$y = \frac 32x - 2$

<u>Second equation</u>

$4x - 2y=4$

$y = 2x - 2$

A linear equation is represented as:

$y = mx + b$

Where b represents the y-intercept

So: By comparison,

$b_1 = 2$ --- the y-intercept of the first equation

$b_2 = 2$ --- the y-intercept of the second equation

2 = 2.

Hence, the y-intercept of $2y = 3x - 4$ and the y-intercept of $4x - 2y=4$ are equal

Read more about y-intercepts at:

brainly.com/question/4015585

6 0

2 years ago

I need help with the last 2 I need the next 3 in the sequence and the nth term

kkurt [141]

Answer:

f. the sequence goes by the half of the previous number.

= 16, 8, 4, 2, 1, 1/2, 1/4, 1/8...

g. the sequence goes by adding the consecutive odd number added to the previous number.

first number= 3.

second number= 3+3

= 6

third number= 6+5

= 11

fourth number= 11+7

= 18

fifth number= 18+9

= 27

sixth number= 27+11

= 38

seventh number= 38+13

= 51, etc.

= 3, 6, 11, 18, 27, 38, 51...

7 0

3 years ago

Alayaa crashed her car through a fence, ran over a garbage can and ran into a tree. The fence will cost $550 to repair, $50 to r

hodyreva [135]

She'll have to pay 20,605

3 0

3 years ago

What is the value of x

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

3 0

1 year ago

Read 2 more answers

A nationwide study of American homeowners revealed that 65% have one or more lawn mowers. A lawnequipment manufacturer, located

GenaCL600 [577]

Answer:

$z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589$

$p_v =P(z>1.589)=0.056$

If we compare the p value obtained with the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

Step-by-step explanation:

Data given and notation

n=497 represent the random sample taken

X=340 represent the homes in Omaha with one or more lawn mowers

$\hat p=\frac{340}{497}=0.684$ estimated proportion of homes in Omaha with one or more lawn mowers

$p_o=0.65$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the true proportion of homes in Omaha with one or more lawn mowers is higher than 0.65.:

Null hypothesis: $p\leq 0.65$

Alternative hypothesis: $p > 0.65$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>1.589)=0.056$

If we compare the p value obtained with the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

7 0

3 years ago