DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
Answer:
Measure of angle XCY is 60°.
Step-by-step explanation:
"Measure of all inscribed angles by the same arc in one segment of the circle are equal"
Using this property in the given circle,
m∠XWY = m∠XCY
60x = 61x - 1
61x - 60x = 1
x = 1
By substituting the value of 'x' in the measure of ∠XCY,
m∠XCY = 61x - 1
= 61(1) - 1
= 61 - 1
= 60°
Therefore, measure of angle XCY is 60°.
Answer:
-12
Step-by-step explanation:
a(b - c)
b = 3, c = -3 and a = -2
-2( 3- -3)
-2(3+3)
-2(6)
-12
Step-by-step explanation:
more information needed
