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13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed
<u>Step-by-step explanation:</u>
Total mass of acid required= 85 ounces
Let the mass of 72% acid be 'a'
Let the mass of 25% acid be 'b'
a + b = 85
b = 85-a
85(40/100) = a(72/100) + b(25/100)
85(2/5) = a(72/100) +(85- a) (25/100)
34 = (72a/100) + (2125/100) - (25a/100)
34 - (2125/100) = (72a + 25a) /100
(3400-2125)/100 = 97a /100
97a = 1275
a = 13.15 ounces
b = 85 - 13.14
b = 71.85 ounces
13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed
Answer: I think he had started with 60 chips!
<em>have a good day/night! :D</em>
Answer: B
Step-by-step explanation:
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Rate = miles / time
8/t = 7/ 35
Dividing by 7
8/t = 7/ 35
8/ 7t = 1/ 35
Multiplying by t
8/7 = t/35
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Options
1) 8/t = 35/ 7 (False, t/8 = 35/ 7 )
2) t/8 = 7/ 35 (False, t/8 = 35/ 7 )
3) 8/7 = t/ 35 (TRUE)
4) 7/8 = t/35 (False, 8/7 = t/ 35 )
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Answer
3) 8/7 = t/ 35 (TRUE)
